How to calculate infinite series?

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To calculate the infinite series Ʃ(2^n * x^n) from n=0 to infinity, it can be transformed by letting X=2x. This allows the series to be recognized as a geometric series, Ʃ(X^n), which has a known sum formula. However, it is crucial to ensure that the condition |X| < 1 is met for the series to converge. This transformation simplifies the calculation significantly. Understanding these conditions is essential for accurately summing the series.
thecaptain90
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Hi, I'm stuck on a problem because I don't know how to calculate this series:
Ʃ(2^n * x^n), n starts from 0 to infinity. How can I calculate this? Do I have to transform it into something else where I know the outcome of the Σ like we do with the geometric functions?
 
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thecaptain90 said:
Hi, I'm stuck on a problem because I don't know how to calculate this series:
Ʃ(2^n * x^n), n starts from 0 to infinity. How can I calculate this? Do I have to transform it into something else where I know the outcome of the Σ like we do with the geometric functions?

Let X=2x
Ʃ(X^n) is the classical geometric series.
 
Thanks, didn't think of doing this.
 
Be advised that |X| < 1 to treat this as a geometric series.
 

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