How to Calculate Kinetic Energy from an Internal Explosion?

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Homework Help Overview

The discussion revolves around a problem involving an internal explosion that breaks an object at rest into two pieces with different masses. The total energy released in the explosion is given as 25000 J, and participants are tasked with determining the kinetic energy acquired by each piece.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the masses of the two pieces, with one piece being 1.6 times the mass of the other. There are attempts to express velocities in terms of each other and to set up equations based on the conservation of energy. Some participants question the correctness of their calculations and the assumptions made regarding the velocities and kinetic energy formulas.

Discussion Status

The discussion is active, with participants sharing their reasoning and calculations. Some have provided guidance on the relationships between kinetic energy and mass, while others are verifying their approaches and calculations. There is a mix of uncertainty and exploration of different interpretations of the problem.

Contextual Notes

Participants express uncertainty about their initial attempts and calculations, indicating a need for clarification on the relationships between mass, velocity, and kinetic energy. The problem's setup and the implications of the explosion on the pieces' motion are also under scrutiny.

Bones
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Homework Statement



An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.6 times the mass of the other. If 25000 J is released in the explosion, how much kinetic energy does each piece acquire?

Homework Equations





The Attempt at a Solution


I am not sure where to begin.
 
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Bones said:

Homework Statement



An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.6 times the mass of the other. If 25000 J is released in the explosion, how much kinetic energy does each piece acquire?

Homework Equations



The Attempt at a Solution


I am not sure where to begin.

Here is a similar problem:
https://www.physicsforums.com/showthread.php?t=267683
 
Ok so m1=1.6m2
How do I figure out v1?
 
Last edited:
Would v1 be 1/1.6v2?
 
Bones said:
Would v1 be 1/1.6v2?

It depends on which piece is the heavier.

What must be true in this problem?
 
The heavier piece will have less velocity than the lighter piece.
 
25000 J = 2.6/1.6 * 1/2 * m2v22
So 25000J*.81=20250J for the lighter piece and 25000J-20250J=4750J for the heavier piece.
Is that correct??
 
Bones said:
25000 J = 2.6/1.6 * 1/2 * m2v22
So 25000J*.81=20250J for the lighter piece and 25000J-20250J=4750J for the heavier piece.
Is that correct??

Not quite.

They want the KE of the pieces. And the KE is mv2/2 not mv2

Check your math.
 
I am not sure what I am doing...that was just kinda of a guess.
 
Last edited:
  • #10
Bones said:
I am not sure what I am doing...that was just kinda of a guess.

25000 J = 2.6/1.6 * 1/2 * m2v22

So what does mv2/2 equal in your equation?

Isn't that the KE of m2?

Isn't that 1 part of what they asked?
 
  • #11
So 25000 J=2.6/1.6*1/2mv2v2^2 which is the same thing as 25000 J=2.6/1.6*mv2v2^2/2

25000J=0.8125m2v2

Am I on the right track?
 
Last edited:
  • #12
Bones said:
So 25000 J=2.6/1.6*1/2mv2v2^2 which is the same thing as 25000 J=2.6/1.6*mv2v2^2/2

Yes but 25000 J = 2.6/1.6 * 1/2*m*v2 = 2.6/1.6 * KE2

Isn't the question "Find KE1 and KE2" ?
 
  • #13
Yes.
So 1.625*KE2=25000
KE2=15385J the lighter piece
KE1=9615J the heavier piece
?
 
  • #14
Bones said:
Yes.
So 1.625*KE2=25000
KE2=15385J the lighter piece
KE1=9615J the heavier piece
?

That's what it looks like.
 
  • #15
Great! Thanks ;)
 

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