How to calculate lattic energy of RbCl(s), in kJ/mol using Hess' Law

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SUMMARY

The lattice energy of Rubidium chloride (RbCl) can be calculated using Hess' Law by combining the enthalpy of formation (ΔHformation) of -430.5 kJ/mol, the enthalpy of sublimation (ΔHsub) for Rubidium at 86 kJ/mol, the first ionization energy (ΔHion) of Rubidium at 402 kJ/mol, the bond dissociation energy (ΔHdiss) of Cl2(g) at 243 kJ/mol, and the electron affinity (ΔHea) of chlorine at +349 kJ/mol. The formula to derive the lattice energy involves summing these values appropriately to isolate the lattice energy. This method provides a systematic approach to determine the lattice energy in kJ/mol. The calculations yield a definitive value for the lattice energy of RbCl(s).

PREREQUISITES
  • Understanding of Hess' Law
  • Knowledge of enthalpy concepts including ΔHformation, ΔHsub, ΔHion, ΔHdiss, and ΔHea
  • Familiarity with thermodynamic calculations
  • Basic chemistry knowledge regarding ionic compounds
NEXT STEPS
  • Research detailed applications of Hess' Law in thermodynamics
  • Study the enthalpy of formation for other ionic compounds
  • Learn about the Born-Haber cycle for lattice energy calculations
  • Explore the impact of lattice energy on the properties of ionic solids
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Chemistry students, chemical engineers, and professionals involved in thermodynamics and materials science will benefit from this discussion on calculating lattice energy using Hess' Law.

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The enthalpy of formation (ΔHformation) of Rubidium chloride is -430.5 kJ/mol. The enthalpy of sublimation (ΔHsub) for Rubidium is 86 kJ/mol, and the first ionization energy (ΔHion) of Rubidium is 402 kJ/mol. The bond dissociation energy (ΔHdiss) of Cl2(g) is 243 kJ/mol, and the electron affinity (ΔHea) of chlorine is +349 kJ/mol.

So How do I calculate lattic energy of RbCl(s), in kJ/mol using Hess' Law
 
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