How to Calculate Mass of a Wire for Measuring Wave Speed

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SUMMARY

The discussion focuses on calculating the mass of a wire necessary for measuring wave speed in a physics experiment. The wave speed is given as 122 m/s, with a tension of 3.13 N and a length of 0.9 m. The correct formula to determine mass per unit length is derived from the equation for wave speed, leading to the conclusion that mass should be calculated in kilograms per meter (kg/m) rather than in grams squared (g/m²). The participant clarifies the misunderstanding regarding the units of tension and mass, emphasizing the importance of unit consistency in calculations.

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  • Familiarity with tension and its units in physics
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  • Basic algebra for rearranging equations and solving for unknowns
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  • Learn about the relationship between tension, mass per unit length, and wave speed
  • Explore unit conversion techniques to avoid common pitfalls in physics calculations
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Homework Statement


I have been writing up a Physics Experiment with working out the speed of waves in a wire.
The wire is stretched across two points which send vibrational pulses down the wire. I am stuck with working out the Mass of the wire throw theoretical methods? hope anyone can help...


Homework Equations


Wave speed=122ms-1
Tension=3.13N1/2
Length=.9m
Mass of length=?


Wave speed=(tension T/mass per unit length)1/2


The Attempt at a Solution


My answer mass=.21029gm^2, just not sure if this is right, it sounds to light for the length of the wire. hope anyone has any ideas ;)
 
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You need to pay better attention to your units. How could the wire have a mass in g 2? is not mass just grams? Also in your post you give the Tension in N 1/2 ? What is that?

All you need do is solve your given expression for mass per unit length. This quantity will have units of [itex]\frac {kg} m[/itex]. Then multiply by your length to get a result in kg.
 
right I see what you mean, sorry about N 1/2 i meant the tension is in Newtons to the power of a half, but i understand why i went wrong, thanks for the help. Cheers Intergral
 

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