How to Calculate Net Impulse from Jumping Motion Analysis

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Trandall
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Homework Statement


A person with a mass of 80.6 kg jumps from a squat position into the air. The velocity
at the beginning of the jump is zero. Fast motion video analysis reveals that the
velocity of the centre of mass at take-off was 5.3 ms-1. Foot contact time when the
ground reaction forces are being generated is 0.25 s. What is the net impulse?


Homework Equations



I = change in p
p = m * v
I = F * t

The Attempt at a Solution



80.6 * 5.3 = 427.18
427.18 * 0.25 = 106.8

Can someone please check this, I think I've made a mistake

Thanks heaps =)
 
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Trandall said:
I = change in p
This is all you need.

80.6 * 5.3 = 427.18
427.18 * 0.25 = 106.8
Why don't you describe what you were doing in each of these calculations? (One makes sense, the other doesn't. :wink:)