How to Calculate pH at Equivalence Point in Titration?

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Discussion Overview

The discussion focuses on calculating the pH at the equivalence point of a titration involving acetic acid and sodium acetate. Participants explore the necessary constants and methods for determining the pH in this context.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a specific titration scenario involving 0.2500 M CH3COONa and 0.1300 M HCl, seeking help with the pH calculation at the equivalence point.
  • Another participant notes that the dissociation constant for acetic acid is needed, indicating that the pH at the equivalence point will be greater than 7 due to the weak acid nature of acetic acid.
  • A participant provides the dissociation constant for acetic acid (Ka = 1.8 x 10^-5) as a reference for the calculation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the calculation method or the final pH value, and the discussion remains unresolved regarding the specific steps to achieve the correct answer.

Contextual Notes

Limitations include the need for further clarification on the calculation steps and the assumptions regarding the behavior of weak acids at the equivalence point.

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A 10.00 mL solution of 0.2500 M CH3COONa is titrated with 0.1300 M HCl to the equivalence point.
CH3COO− + H+ → CH3COOH
volume of HCl required=19.23 mL

Calculate the pH of the solution at the equivalence point.

I've tried this a million ways and still keep getting it wrong. Also, my chemistry prof doesn't respond or have office hours so I'm kind of on my own :( Thank you in advance for your help :).
 
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You need the dissociation constant for acetic acid. It is a weak acid, and therefore the equivalence point pH will be greater than 7.
 
Dissociation constant for CH3COOH
Ka = 1.8 x 10^-5
 

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