How to Calculate Photon Strike Rate for Monochromatic Light?

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SUMMARY

The calculation of the photon strike rate for monochromatic light with a wavelength of 300 nm and an intensity of 15x10^-2 W/m² on a surface area of 4 cm² can be determined using the formula for photon energy, E = hc/λ. The power incident on the surface is calculated as power = intensity × area, leading to the equation for the number of photons per second: No.photons/s = (15 × 10^-2 W/m² × 4 × 10^-4 m²) / (hc/λ). This approach effectively eliminates time from the equation, allowing for a clear calculation of photon strike rate.

PREREQUISITES
  • Understanding of photon energy calculation using E = hc/λ
  • Knowledge of light intensity and its relation to power and area
  • Familiarity with basic physics concepts such as energy transfer and time
  • Ability to manipulate equations to isolate variables
NEXT STEPS
  • Research the constants h (Planck's constant) and c (speed of light) for accurate calculations
  • Learn about the implications of light intensity on photon flux
  • Explore the concept of monochromatic light and its applications in physics
  • Study related topics such as the photoelectric effect and its dependence on photon energy
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Students and professionals in physics, particularly those studying optics and photonics, as well as anyone interested in understanding the behavior of light and its interaction with surfaces.

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Monochramatic light of wavelength 300 nm is incident normally on a surface of area 4 cm squared. If the intensity of the light is 15x10^-2 W/m^2, determine the rate at which photons strike the surface.

Honestly when reading this I thought I missed something in the chapter. A wave of 300nm strikes a metal surface that is 4 centimeters squared. The light intensity strikes with 15x10^-2. I am just lost on how to start it because I haven't seen anything like it in this chapter.
 
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I = power/ area
power = energy / time
energy of each photon is given by hc/lambda
so the energy of a certain number,n of photons is nhc/lambda
im not quite sure how to eliminate the time in the equation you will get... perhaps someone else will helpm since i too am curious on how to solve something like this
 
The rate of photons means #of photons each second.The # of photons can be computed by dividing the transferred energy to the surface by the energy of one photon...That "/s" is gotten by diving the power (energy in unit time) and not the energy.

\mbox{No.photons \ per \ s}=\frac{15\cdot 10^{-2} \ \frac{W}{m^{2}}\cdot 4\cdot 10^{-4}m^{2}}{\frac{hc}{\lambda}}

Daniel.
 
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ok sorry i don't mean to hijack your thread but dexter can u take a look at my thread on index of refraction i nteh college level forum?
 
Thanks, that helps a lot..made it a lot clearer
 

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