How to Calculate Q, W, ΔU, and ΔH for Ideal Gas Compression Processes?

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Homework Help Overview

The discussion revolves around calculating thermodynamic properties (Q, W, ΔU, and ΔH) for an ideal gas undergoing various compression processes, including isothermal and adiabatic changes. The problem presents specific initial conditions and asks for analysis of multiple processes without providing the number of moles or initial temperature.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the implications of missing information, particularly the number of moles and initial temperature, on the calculations. There is a discussion on expressing the properties in terms of available variables like pressure and volume.

Discussion Status

The conversation is ongoing, with participants questioning the assumptions made about ΔU and ΔH being zero. Some suggest that the ideal gas law can provide sufficient information to express the desired properties in terms of known variables.

Contextual Notes

There is a noted lack of initial temperature and the number of moles, which are critical for the calculations. Participants are considering how to approach the problem under these constraints.

zulfiqar6
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Homework Statement


An ideal gas, Cp = (5/2)R, Cv = (3/2)R, is changed from P1 = 1 Bar and V1t = 12m^3 and V2t = 1m^3 by the following mechanically reversible processes:
a) Isothermal compression
b) Adiabatic compression followed by cooling at constant temperature
c) Adiabatic compression followed by cooling at constant volume
d) Heating at constant volume followed by cooling at constant pressure
e) cooling at constant pressure followed by heating at constant volume

find Q, W, ΔU, ΔH, and sketch a PV diagram for each process.

Homework Equations



PV=nRT

For isothermal process (a): Q = -W = RTln(V2/V1)

for isobaric processes: Q = ΔH = ∫Cp dT
Adiabatic Processes: TV^(γ-1) = const, TP^(1-γ)/γ = const, PV^γ = const,
for Isochoric processes: Q = ΔU = ∫Cv dT

The Attempt at a Solution



I know that ΔU = 0 and ΔH = 0
moles aren't given. I can't find any way to get the initial temperature, which is needed for most of the calculations.
 
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zulfiqar6 said:
I know that ΔU = 0 and ΔH = 0
Why is that?

zulfiqar6 said:
moles aren't given. I can't find any way to get the initial temperature, which is needed for most of the calculations.
Indeed, there is not enough information. Either give results as a function of ##n## or ##T##, or assume 1 mole.
 
DrClaude said:
Indeed, there is not enough information. Either give results as a function of ##n## or ##T##, or assume 1 mole.

Since it is an ideal gas, there is enough information because you can express Q, W, ΔU, ΔH in terms of P1, P2, V1, and V2 using nT = PV/R

AM
 
Andrew Mason said:
Since it is an ideal gas, there is enough information because you can express Q, W, ΔU, ΔH in terms of P1, P2, V1, and V2 using nT = PV/R
Right. Forget my previous comment.
 

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