How to Calculate Relativistic Momentum Using M, m, and c?

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Homework Help Overview

The discussion revolves around calculating the relativistic momentum of a particle with mass m resulting from the disintegration of a particle with mass M at rest. The problem requires expressing the momentum in terms of M, m, and c only.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of mass-energy and momentum equations. There are attempts to manipulate these equations to express momentum without the velocity variable v. Some participants suggest using energy and momentum quantities for all involved particles.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to eliminate variables and derive the momentum expression. Some guidance has been offered regarding the use of specific equations in special relativity, but no consensus has been reached on a clear path forward.

Contextual Notes

Participants are constrained by the requirement to express the answer solely in terms of M, m, and c, which complicates the manipulation of the equations. There is also an emphasis on avoiding certain variables that may complicate the calculations.

Saptarshi Sarkar
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Homework Statement
A particle X of mass M at rest disintegrates into a particle of mass m and another massless particle. Calculate the momentum of m.
Relevant Equations
What I figured:

From conservation of mass-energy
##Mc^2 = \frac {mc^2} {\sqrt {1 - \frac {v^2} {c^2}}}+ pc##

From conservation of momentum
##0 = \frac {mv} {\sqrt {1 - \frac {v^2} {c^2}}} + p##
The answer is required to be in terms of M,m and c only. But, I am not able to calculate the momentum of the m mass particle using the above two. Can anyone help me by telling me what I am missing?
 
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Saptarshi Sarkar said:
Homework Statement:: A particle X of mass M at rest disintegrates into a particle of mass m and another massless particle. Calculate the momentum of m.
Homework Equations:: What I figured:

From conservation of mass-energy
##Mc^2 = \frac {mc^2} {\sqrt {1 - \frac {v^2} {c^2}}}+ pc##

From conservation of momentum
##0 = \frac {mv} {\sqrt {1 - \frac {v^2} {c^2}}} + p##

The answer is required to be in terms of M,m and c only. But, I am not able to calculate the momentum of the m mass particle using the above two. Can anyone help me by telling me what I am missing?

Try working with the quantities ##E## and ##p## for all particles involved.
 
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Saptarshi Sarkar said:
The answer is required to be in terms of M,m and c only. But, I am not able to calculate the momentum of the m mass particle using the above two. Can anyone help me by telling me what I am missing?

You are missing that you *can* calculate the momentum of m using those equations. Two equations, two unknowns.
 
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DEvens said:
You are missing that you *can* calculate the momentum of m using those equations. Two equations, two unknowns.

From the second equation I found the momentum to be equal to -p, but when I try to get the value to -p using the equation for conservation of mass-energy, I am not able to eliminate the v.
 
Saptarshi Sarkar said:
From the second equation I found the momentum to be equal to -p, but when I try to get the value to -p using the equation for conservation of mass-energy, I am not able to eliminate the v.
Then don't have the ##v## in your equations in the first place. ##v## and ##\gamma## just get in the way.
 
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Saptarshi Sarkar said:
Can anyone help me by telling me what I am missing?

Probably the most important equation in SR is $$E^2 = p^2c^2 + m^2c^4$$
Which holds for both massive and massless particles.
 
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For a more systematic approach,try working with conservation of 4 momentum and using the fact that(c=1):

$$P.P=m^2 $$
$$P= P_1 + P_2$$
 
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