How to calculate resultant vector angle?

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The discussion focuses on calculating the resultant vector angle from a person's displacement along four straight lines at different angles. The resultant displacement was determined to be 512.8, and the challenge is to find the direction measured from due west, with counterclockwise as the positive direction. A participant initially calculated the angle as 237.26 degrees but found it incorrect, questioning how to adjust this measurement from due west. The consensus is that the angle can be adjusted by subtracting or adding 180 degrees, leading to the correct angle of 57.26 degrees from due west. Clear diagramming is recommended to visualize the angles accurately.
euphtone06
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1. A person walks in a path which consists of four straight lines at different angles and lengths as seen in the attached image. http://img253.imageshack.us/img253/244/problemlt5.gif
The first part of the problem was to find the resultant displacement which was found to be 512.8. The second part asks what is the direction measured from due west, with counterclockwise being in the positive direction of the person's resultant displacement?


The Attempt at a Solution


I am having a hard time understanding what the problem means by measured from due west I found the angle of the typical resultant displacement to be 237.26 degrees but this answer was wrong. Is it simply adding +/- 180 for due west? I am confused
 
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euphtone06 said:
I am having a hard time understanding what the problem means by measured from due west
For example, if the displacement was due east it would be 180 degrees as measured from due west.
I found the angle of the typical resultant displacement to be 237.26 degrees but this answer was wrong.
What are you measuring your angle with respect to? (From due east, I presume.)
Is it simply adding +/- 180 for due west?
Yes, it's as simple as that. But draw a careful diagram to figure it out.
 
Yes I measured the angle from due east so 237.26-180= 57.26 would be my answer from due west?
 
Sounds good to me. (I didn't check your original answer though.)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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