How to calculate the AH capacity of a battery?

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    Battery Capacity
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Discussion Overview

The discussion centers on calculating the milliamp-hour (mAH) capacity of a homemade vinegar battery, exploring methods to measure its output and reduce resistance within the battery. The scope includes practical experimentation and conceptual understanding related to battery design and performance.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant inquires about calculating the mAH rating of their vinegar battery, expressing a willingness to fully discharge it for measurement.
  • Another suggests connecting the battery to a load and using a mA meter to record readings over time, proposing to plot a graph of mA versus time.
  • One participant proposes reducing resistance by moving the cathode and anode closer together, while also considering the effects on voltage and surface area.
  • There are suggestions to add powdered conductors to the vinegar to improve conductivity, though concerns about voltage effects are raised.
  • Another participant notes that the less current drawn from the battery, the more capacity it will have, emphasizing that AH is a unit of measure for charge capacity.
  • Questions are raised about the relationship between moving the electrodes and voltage changes, with one participant reflecting on past experiences with battery resealing.
  • Concerns about loose electrical connections causing issues are mentioned, indicating potential complications in battery performance.

Areas of Agreement / Disagreement

Participants express various ideas on how to measure and improve the battery's performance, but there is no consensus on the best methods or the implications of their proposed changes. The discussion remains unresolved regarding the optimal approach to calculating mAH and reducing resistance.

Contextual Notes

Participants mention various assumptions about the effects of electrode positioning and the addition of conductors, but these are not fully explored or validated within the discussion.

Stephenk53
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Summary

I made a vinegar battery that appears to only output .001A of current. I made it very quickly because I had to change my design for a project last minute due to my inability to get a voltage regulator in time. So it is so bad I doubt I could have made a worse battery. Anyway, the project was a rechargeable flashlight and it has already been graded which is why I am not putting this in a homework forum. So how would I find out its mAH rating? I would like to know for knowings sake rather than actual need so if I have to fully discharge the battery to do so that is fine.

Questions
How to calculate the AH
How would I lower the resistance in the battery?
 
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Hi Stephenk53. :welcome:

If you connect your battery to a load, and include your mA meter in the circuit, then record the meter's reading at regular intervals and plot a graph: mA versus time (in hours). The area under your curve will have units of ...?

What are your thoughts on how you might go about reducing the cell's resistance?

It still belongs in the homework subforum because it resembles typical homework.
 
To reduce the resistance I thought I could move the cathode and anodes of the cells closer together within each cell, although that would reduce voltage but I could change that by increasing surface area of the cathodes and anodes. I could try adding something that is a powdered conductor such as salt into the vinegar or metal powder of a different material as the cathodes and anodes. But if I add a conductor of some kind I would think that would affect the voltage in some way.

As for recording the mA I think I would have some sort of camera record a constant reading from the mA meter to keep track of possible spikes in the readings.
 
Stephenk53 said:
To reduce the resistance I thought I could move the cathode and anodes of the cells closer together within each cell
That is a reasonable thing to try.

although that would reduce voltage
Why do you think that might happen?

but I could change that by increasing surface area of the cathodes and anodes.
That is another change you could investigate, it may achieve what you are hoping. As might a different electrolyte, or maybe just a more concentrated version of the electrolyte you are using.

If your setup is not disturbed, there should not be any abrupt changes in current, just a gradual reduction as your battery goes flat.
 
The less current you draw, the more capacity the cell will have. Note that AH (or more properly A-hr) is a unit of measure. Charge capacity is the corresponding physical quantity.
 
NascentOxygen said:
Why do you think that might happen?

I think it would happen because that is what appeared to occur when I had moved the cathode and anodes when I was resealing one of the batteries that had a leak
 
Stephenk53 said:
I think it would happen because that is what appeared to occur when I had moved the cathode and anodes when I was resealing one of the batteries that had a leak
It may have been a loose lead. Movement of electrical connections is the cause of a lot of problems.
 

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