How to Calculate the Attraction Between Two Solenoids in Series?

  • Thread starter Thread starter LordBerkley
  • Start date Start date
  • Tags Tags
    Attraction
Click For Summary
SUMMARY

The discussion focuses on calculating the attraction between two solenoids arranged in series (N-S N-S) with a separation distance 'x'. The initial approach utilized the equation for the attraction between cylindrical bar magnets, which is deemed inappropriate for solenoids. The correct method involves calculating the magnetic field generated by each solenoid and applying the force between parallel current-carrying wires, considering the winding density and performing continuous integration to account for all loops in the solenoids.

PREREQUISITES
  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the force between parallel current-carrying wires
  • Knowledge of continuous integration techniques
  • Basic principles of magnetic flux density and its calculation
NEXT STEPS
  • Study the calculation of magnetic fields in solenoids using Ampère's Law
  • Learn about the force between parallel wires carrying current, specifically the formula F = (μ₀/2π) * (i₁ * i₂) / d
  • Explore continuous integration methods for calculating forces in systems with multiple loops
  • Investigate the impact of winding density on magnetic field strength and attraction
USEFUL FOR

This discussion is beneficial for electrical engineers, physicists, and students studying electromagnetism, particularly those interested in solenoid applications and magnetic force calculations.

LordBerkley
Messages
15
Reaction score
0
I have been asked to calculate the attraction between two solenoids that are positioned in 'series' N-S N-S and have a space 'x' between them.

I tried to approximate the attraction between them by using the equation for attraction between cylinderical bar magnets:


F=\left[\frac {B_0^2 A^2 \left( L^2+R^2 \right)} {\pi\mu_0L^2}\right] \left[{\frac 1 {x^2}} + {\frac 1 {(x+2L)^2}} - {\frac 2 {(x+L)^2}} \right]

where

B0 is the magnetic flux density very close to each pole, in T,
A is the area of each pole, in m2,
L is the length of each magnet, in m,
R is the radius of each magnet, in m, and
x is the separation between the two magnets, in m

(its from http://en.wikipedia.org/wiki/Force_between_magnets)

I have been told this is not an appropriate equation. Can anyone help me understand why, and what I should do instead?

Any advice much appreciated.


LB
 
Physics news on Phys.org
Forgot to mention, I know the size of solenoids and the flowing current so I could calculate the magnetic field size to use in the bar magnet equation.
 
My stab at it:

Each solenoid has N turns. Using the formula for the force between two parallel wires carrying currents iA and iB, take the loop of solenoid A closest to solenoid B and determine the force between it and the closest loop of solenoid B. Then take the closest loop of A and get the force between it and the second-closest loop of B, etc. Then repeat for all the loops of A.

You don't want a discrete formula so assume a winding density of n turns/unit length and do a continuous integration.

Hopefully you'll get other suggestions. Not sure this is the best way to proceed.
 
  • Like
Likes   Reactions: 1 person

Similar threads

Replies
0
Views
1K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K