How to calculate the contraction of metric tensor g^ab g_ab

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Discussion Overview

The discussion revolves around the calculation of the contraction of the metric tensor \( g^{ab} g_{ab} \). Participants explore the steps involved in this calculation, addressing misunderstandings related to tensor algebra and the properties of the metric tensor.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in calculating the contraction \( g^{ab} g_{ab} \) and questions their approach, suggesting that they believe it should equal \( \delta_{aa} \).
  • Another participant clarifies that the contraction involves summing over all indices, providing an example of the terms involved.
  • There is a challenge to the initial reasoning, with a focus on the misunderstanding of the last step in the calculation, specifically regarding the value of \( \delta^a{}_a \).
  • One participant points out that in four spacetime dimensions, \( \delta^a{}_a \) equals 4, indicating a need to sum over the components correctly.
  • A later reply acknowledges the need to expand and sum over the components of the metric tensor rather than treating \( \delta^a{}_a \) as the components directly.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to the contraction calculation, with multiple viewpoints and some confusion remaining regarding the properties of the metric tensor and the summation process.

Contextual Notes

Limitations include potential misunderstandings of tensor notation and the properties of the metric tensor, as well as the specific dimensional context affecting the calculations.

yicong2011
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I wish I could calculate the contraction:

gabgab

I wish someone could show me how to get n!

Unfortunately, I find it difficult, for I am not familiar with Tensor Algebra ...
My wrong way to calculate it:

gabgab= gabgba (since gab is symmetric)

= δaa

= 1Why is it wrong?
 
Last edited:
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So, you just sum over a and b...so it's like g00g00+g01g01+g02g02+g03g03+g10g10+g11g11+...all 16 terms
 
But why the following is wrong? I cannot figure it out...


yicong2011 said:
gabgab= gabgba (since gab is symmetric)

= δaa

= 1

Anyone can help?
 
The problem is your last step.

In four spacetime dimensions
[tex]\delta^a{}_a = 4[/tex]
because
[tex]\delta^a{}_a = \delta^0{}_0 + \delta^1{}_1 + \delta^2{}_2 + \delta^3{}_3 = 1 + 1 +1 +1 = 4[/tex]
 
JustinLevy said:
The problem is your last step.

In four spacetime dimensions
[tex]\delta^a{}_a = 4[/tex]
because
[tex]\delta^a{}_a = \delta^0{}_0 + \delta^1{}_1 + \delta^2{}_2 + \delta^3{}_3 = 1 + 1 +1 +1 = 4[/tex]

Ahh...Ja... [tex]\delta^a{}_a is not the components... I need to expand it and sum over the components...[/tex]
 

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