How to Calculate the Empirical Formula of a Hydrate?

Click For Summary
SUMMARY

The empirical formula of a hydrate can be calculated using the mass of the anhydrous salt and the mass of water lost during hydration. In this case, the mass of MnSO4·XH2O is 1.8g, the mass of the anhydrous MnSO4 is 1.59g, and the mass of water is 0.21g. To find the molar ratio, divide the mass of the anhydrous salt by its molar mass, and the mass of water by the molar mass of water (18.02 g/mol). This will yield the ratio of moles of MnSO4 to moles of water, allowing for the determination of the empirical formula.

PREREQUISITES
  • Understanding of molar mass calculations
  • Knowledge of empirical formulas
  • Familiarity with hydrates and their properties
  • Basic skills in stoichiometry
NEXT STEPS
  • Learn how to calculate molar mass for various compounds
  • Study the concept of hydration and its effects on chemical formulas
  • Explore stoichiometric calculations involving hydrates
  • Investigate common hydrates and their empirical formulas
USEFUL FOR

Chemistry students, educators, and anyone involved in laboratory work related to chemical compounds and their properties.

unf0r5ak3n
Messages
35
Reaction score
0

Homework Statement


Calculate the empirical formula of each hydrate


Homework Equations



Mass of MnSO4 x XH2O...
-Hydrate = 1.8g
-Anhydrous salt = 1.59g
-Water = .21g


The Attempt at a Solution



I thought you would set 1.8g MnSO4*XH2O((Molecular mass of MnSO4)/(Molecular mass of MnSO4*XH2O)), but I am not sure what to do.
 
Physics news on Phys.org
You have to find the molar ratio between anhydrous salt and water.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 3 ·
Replies
3
Views
8K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
18K