How to calculate the lattice sums of BCC?

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SUMMARY

The calculation of lattice sums A12 and A6 for a Body-Centered Cubic (BCC) structure involves specific distance formulas for nearest and second nearest neighbors. The user calculated A12 as 8.097 using the formula A12 = 8(1/1)^12 + 6(1/root2)^12 + 12(1/2)^12 + 16(1/root5.5)^12 + 8(1/root6)^12. It was noted that the coefficient for the second nearest neighbor should be adjusted to (sqrt(3)/2)^12 to accurately reflect the distance of a body diagonal. This correction is essential for precise calculations in crystallography.

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How do I calculate the lattice sums A12 and A6 for a BCC structure?

I have calculated the following so far:

A12 = 8(1/1)^12 + 6(1/root2)^12 + 12(1/2)^12 + 16(1/root5.5)^12 + 8(1/root6)^12 = 8.097.

Have i made any mistakes? Are my nearest neighbour values correct? Please help! o:)
 
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ilovecubes said:
How do I calculate the lattice sums A12 and A6 for a BCC structure?

I have calculated the following so far:

A12 = 8(1/1)^12 + 6(1/root2)^12 + 12(1/2)^12 + 16(1/root5.5)^12 + 8(1/root6)^12 = 8.097.

Have i made any mistakes? Are my nearest neighbour values correct? Please help! o:)

Second nearest neighbors distance is a (lattice constant).
First n.n. distance is a*sqrt(3)/2 (half body diagonal)
So the coefficient in the second term should be (sqrt(3)/2)^12.
 

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