How to calculate the magnitude of a function?

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Homework Help Overview

The discussion revolves around calculating the magnitude of the function G(w) = 1/(jωτ + 1). Participants are exploring how to find the magnitude of a complex function, which involves separating real and imaginary components.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the process of dividing the function and express uncertainty about how to correctly separate real and imaginary parts to find the magnitude. There are suggestions to multiply by a conjugate to simplify the expression.

Discussion Status

There are various attempts to clarify the approach to finding the magnitude, with some participants providing suggestions on manipulating the function. The discussion reflects a mix of interpretations and methods being considered, but no consensus has been reached yet.

Contextual Notes

Some participants question the method of division used and suggest alternative approaches, indicating a need for clearer understanding of complex function manipulation. There is also a note on the proper formatting of mathematical expressions in LaTeX.

seto6
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Homework Statement


I have this function:

G(w)=\frac{1}{j\omega\tau+1}
I want to find the magnitude

Homework Equations


S=\alpha+j\beta

magnitude(S)=\sqrt{\alpha^{2}+\beta^{2}}3. The Attempt at a Solution [/b

What i did was carry out the division,

so i got
\frac{j\omega\tau-1}{-(j\omega+1)}
then do i just split it into real and imaginary part and then take the magnitude using this?
S=\alpha+j\beta

magnitude(S)=\sqrt{\alpha^{2}+\beta^{2}}

Can anyone help i am not so sure how to approach this?
 
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seto6 said:
What i did was carry out the division,

so i got
\frac{j\omega\tau-1}{-(j\omega+1)}

This is where you got it wrong. Try to multiply the numerator and the denominator of the original G(ω) by - j ω \tau + 1 and see what you get.
 
Then, try and think what you had to multiply by the expression - j ω \tau + 1 to get your answer.
 
seto6 said:

Homework Statement


I have this function:

G(w)=\frac{1}{j\omega\tau+1}
I want to find the magnitude

Homework Equations


S=\alpha+j\beta

magnitude(S)=\sqrt{\alpha^{2}+\beta^{2}}


3. The Attempt at a Solution [/b

What i did was carry out the division,

so i got
\frac{j\omega\tau-1}{-(j\omega+1)}
then do i just split it into real and imaginary part and then take the magnitude using this?
S=\alpha+j\beta

magnitude(S)=\sqrt{\alpha^{2}+\beta^{2}}

Can anyone help i am not so sure how to approach this?


Failexam's suggestions are all you need to do. However, if you are going to use LaTeX, why not do it properly? Your expression for "magnitude(S)" is ugly; here is what it should look like: \text{magnitude}(S)=\sqrt{\alpha^2 + \beta^2}. To get this, just remove the "inner" [i t e x]-[/i t e x] pairs; furthermore, if you want the word "magnitude" to appear in nice text font, just include it inside the [i t e x] command, but say \text{magnitude}.

RGV
 
The magnitude of two vectors divided is the division of the magnitudes. What is the magnitude of the numerator? What is the magnitude of the denominator? What is the result of dividing those magnitudes?
 

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