How to Calculate the Net Force on a Rectangular Loop by a Straight Wire?

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To calculate the net force on a rectangular loop by a straight wire, the current values and dimensions of both the wire and loop must be considered. The magnetic field produced by the straight wire affects the loop, with forces acting on its sides depending on their orientation relative to the wire. The equations for magnetic force and field must be applied correctly, taking into account the contributions from each side of the loop. The net force is determined by finding the resultant of the forces acting on the loop's sides, which experience opposite forces due to their parallel alignment with the wire. Accurate calculations are essential to determine the correct magnitude and direction of the net force.
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Homework Statement



In the figure below, the current in the long, straight wire is I1 = 4.8 A, and the wire lies in the plane of the rectangular loop, which carries 9.7 A. The dimensions shown are c = 0.10 m, a = 0.15 m, and l = 0.45 m. Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop.

Homework Equations



F/l = (1.26E-6)(I1)(I2)/(2)(pi)(d)

F= IlBsin(theta)

B=(1.26E-6)(I)/(2)(pi)(r)

The Attempt at a Solution



I figured that we would have to use a combination of the three equations above, and I got an answer of 4.2E-5, but this is incorrect. I believe this answer only takes into account the two wires, not the wire and the rectangle. I am not really sure how to take into account the rectangle. Please help!
 

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Sides of the rectangle parallel to the wire will experience opposite forces. Find the resultant to get the net force.
 

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