How to Calculate the Net Force on a Rectangular Loop by a Straight Wire?

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SUMMARY

The discussion focuses on calculating the net force exerted by a straight wire on a rectangular loop carrying current. The wire has a current of I1 = 4.8 A, while the loop carries 9.7 A. Key equations used include F/l = (1.26E-6)(I1)(I2)/(2)(pi)(d) and B = (1.26E-6)(I)/(2)(pi)(r). The correct approach involves considering the forces on both sides of the rectangular loop, which are parallel to the wire and experience opposite forces, leading to a resultant net force calculation.

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  • Knowledge of vector forces and their resultant calculations
  • Basic principles of electromagnetism and Lorentz force
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Homework Statement



In the figure below, the current in the long, straight wire is I1 = 4.8 A, and the wire lies in the plane of the rectangular loop, which carries 9.7 A. The dimensions shown are c = 0.10 m, a = 0.15 m, and l = 0.45 m. Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop.

Homework Equations



F/l = (1.26E-6)(I1)(I2)/(2)(pi)(d)

F= IlBsin(theta)

B=(1.26E-6)(I)/(2)(pi)(r)

The Attempt at a Solution



I figured that we would have to use a combination of the three equations above, and I got an answer of 4.2E-5, but this is incorrect. I believe this answer only takes into account the two wires, not the wire and the rectangle. I am not really sure how to take into account the rectangle. Please help!
 

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Sides of the rectangle parallel to the wire will experience opposite forces. Find the resultant to get the net force.
 

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