How to Calculate the Required Angular Velocity of an Ultracentrifuge?

[courtrigrad]

Find the required angular velocity of an ultracentrifuge in \frac{rev}{min} for the radial acceleration of a point 1.00 cm from the axis to equal 400,000g (that is, 400,000 times the acceleration of gravity.)
So a_{rad} = (\omega)^{2}r. 400,000g = \omega^{2}(0.01 m). Would I just solve for \omega? \omega would be in m/s? Then to convert to rev/min, you use the fact that 2\pi(0.01 m) equals 1 revolution?
Would this be the correct way to solve this problem?
Thanks
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[andrevdh]

when you solve for \omega with your formula the units is rad/s (if you worked in SI units), which needs to be converted to rev/min now
2\pi\ rad=\ 1\ rev
therefore
1\ rad=\ \frac{1}{2\pi}\ rev
and since
60\ s=\ 1\ min
it follows that
1\ s=\ \frac{1}{60}\ min
therefore
\omega\ =\ \frac{1\ rad}{1\ s}\ =\ \frac{60\ rev}{2\pi\ min}\ =\ \frac{30}{\pi}\ rev/min