How to calculate this probability (conditional distributions)

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SUMMARY

The probability density function fXY(x,y) is defined as 2 for the region where 0 < x < 1 and x < y < 1, and 0 elsewhere. The calculation of P((x > 0.5) ∩ (y < 0.5)) results in 0, as the density function is 0 for the area where x > y. This conclusion is supported by the provided figures and the integration method used in previous exercises, confirming that the surfaces do not intersect in this case.

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Drao92
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fXY(x,y)=2 if 0<x<1 and x<y<1, 0 for other intervals
I have to calculate: P((x>0.5)π(y<0.5)).
I think it 0 but I am not sure because in all other exercises I've made the surfaces intersect each other. Like in fig 1 for P((x<0.5))π(y<0.5))=integral from 0 to 0.5 from integral from x to 0.5 from 2dydx.
The fig 2 is for P((x>0.5)π(y<0.5)).
Im sorry because i forgot to mark the axis. vertical is y and horizontal is x.I apologize.
https://www.physicsforums.com/attachment.php?attachmentid=58161&stc=1&d=1366802927
https://www.physicsforums.com/attachment.php?attachmentid=58162&stc=1&d=1366802927
 

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If I understand your description, the density function = 0 for x > y. Therefore P((x > 0.5) and (y < 0.5)) = 0.
 

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