- #1

alberto91

- 15

- 19

Is this correct?

Why the time is minutes instead of seconds?

Thanks!

Why the time is minutes instead of seconds?

Thanks!

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- Thread starter alberto91
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- #1

alberto91

- 15

- 19

Is this correct?

Why the time is minutes instead of seconds?

Thanks!

Why the time is minutes instead of seconds?

Thanks!

- #2

WWGD

Science Advisor

Gold Member

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By dimensional analysis your t has no units.

- #3

alberto91

- 15

- 19

By dimensional analysis your t has no units.

And how can I calculate that equation?

- #4

WWGD

Science Advisor

Gold Member

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- #5

alberto91

- 15

- 19

Thanks for your answer.

I want to use delta-vee (dv)

- #6

mfig

- 282

- 97

To find the time you need a relationship between velocity and time such as the definition of acceleration:

##\frac{dv}{dt}=a##

Then separate and integrate:

##dv=adt \rightarrow \int_{0}^{v_{needed}} dv = \int_{0}^{t_{needed}}a dt##

This gives

##v_{needed} = at_{needed}##

So to find the time needed to get to the needed velocity, simply divide.

##t_{needed} = v_{needed}/a##

Note that this assumes constant acceleration from zero. So it seems the solution you showed has the wrong units for acceleration.

##\frac{dv}{dt}=a##

Then separate and integrate:

##dv=adt \rightarrow \int_{0}^{v_{needed}} dv = \int_{0}^{t_{needed}}a dt##

This gives

##v_{needed} = at_{needed}##

So to find the time needed to get to the needed velocity, simply divide.

##t_{needed} = v_{needed}/a##

Note that this assumes constant acceleration from zero. So it seems the solution you showed has the wrong units for acceleration.

Last edited:

- #7

mfb

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