High School Why do we use squared quantities in equations and formulae?

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Squared quantities are used in equations because they focus on the magnitude of values, such as velocity, without considering direction. This approach simplifies calculations, especially in physics, where distance is derived from the product of velocity and time. The discussion also highlights that the square root function is defined to yield a non-negative result, which is crucial for maintaining the function's single-valued nature. Additionally, while multiple values can exist in certain contexts, such as projectile motion, the use of squared terms helps ensure continuity and clarity in mathematical expressions. Overall, the use of squared quantities is essential for accurate and consistent mathematical modeling.
  • #31
etotheipi said:
@sophiecentaur I really have a hard time understanding what you're trying to say. The fact that functions are single valued (by definition) is a critical property.
Strongly agree. In the example posted by @sophiecentaur, ##x^2 + y^2 = 1##, y is most definitely NOT a function of x. The same is true for the other conic sections. For the circle equation, solving for y yields ##y = \pm \sqrt{1 - x^2}##, so for each x, with ##x \ne \pm 1##, there are two y values.
sophiecentaur said:
Afaics, it's important to qualify statements about the 'meaning' of Root x.
No. Although a positive real number has two square roots, the symbol ##\sqrt x## is taken by convention to mean the principal, or positive square root. Why else do you think there's a +/- symbol in the Quadratic Formula; i.e., the solutions to ##ax^2 + bx + c = 0## are given by ##x = \frac{b^2 \pm \sqrt{b^2 - 4ac}}{2a}##.
sophiecentaur said:
I think you mean a continuously differentiable function. There are plenty of functions with first derivatives that aren't continuous. Triangular waves, cycloids and x2 = y
No, he (@etotheipi) meant plain old functions. BTW, ##x^2 = y## is continuous and has derivatives of all orders. ##\frac{dy}{dx} = 2x##. OTOH, if you meant ##y^2 = x \Leftrightarrow y = \pm \sqrt x##, then y is not a function of x. (Each positive x value is paired with two y values.)
sophiecentaur said:
Perhaps the vocabulary has changed in 50 years. (Which is possible.)
No, it hasn't. From Calculus and Analytic Geometry, by Abraham Schwartz, 2nd Ed., published in 1967: (emphasis added by me)
Function; domain; range. We are given a set of numbers, which we shall call the domain D, and instructions for associating a number y with each number x of D. The set of all numbers y associated with numbers x of D shall be called the range R. The correspondence thus created between the sets D and R shall be called a function.
The relationship here is either a one-to-one relationship (e.g. y = f(x) = 2x) or many-to-one (e.g., y = g(x) = sin(x). By definition, a function cannot be one-to-many (e.g. ##y^2 = x## or equivalently ##y = \pm \sqrt x##).
The First Edition appeared in 1960, which is 60 years ago. I'm positive the definition of a function didn't change between the two editions.
sophiecentaur said:
"By definition" is too strong. You are stating that the default actually exists.
No, "by definition" is not too strong. One definition of the absolute value is ##|x| = \sqrt{x^2}##, for all real numbers x.

A.T. said:
How can "by definition" be too strong? It just a convention about what a word means in a certain context, that is most widely accepted.
 
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  • #32
I do take all of your points and I clearly have mistaken how the word "function" is strictly defined. So the term is mi-used a lot? Perhaps and it wouldn't be the only commonly mis-used term.
 
  • #33
sophiecentaur said:
I do take all of your points and I clearly have mistaken how the word "function" is strictly defined. So the term is mi-used a lot? Perhaps and it wouldn't be the only commonly mis-used term.
Yes, it's misused a lot. A test that can be used to determine whether a graph represents a function is the vertical line test. If a vertical line is swept along the horizontal axis and never intersects more than one point, the graph is that of a function. This would show that the graph of a circle isn't that of a function, nor is the graph of the other conic sections, including, say, ##y^2 = x##.
Also, we have had many threads over the years where people are confused about the meaning of ##\sqrt x##, thinking that it represents two values.
 
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  • #34
Mark44 said:
Also, we have had many threads over the years where people are confused about the meaning of ##\sqrt x##, thinking that it represents two values.
Ahh - and the 'quadratic solving formula' actually includes the term +/-√(4ac) to take care of that. It was hiding from me in plain sight!
 
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