i think so. It looks correct, with condition you won't get perfect lay on the wires so it'll usea kittke nore that 12.24 cm2Suppose I use #17 gauge wire as per my table for primary winding so wire diameter is 1.42mm. so turn per cm2 is 10/1.42= 7.04, so 7.04*7.04=49 turn per cm2.
nearly 600 turn for primary. so 600/49=12.24cm2 window are required is it right sir.
Have you tried your spreadsheet , the one you used for your transformer ?
no datasheet for core but manufacture test core with 10 turn and volt is 3.95.
0.395 volts per turn equates to how much flux ? 0.395 /100pi = 1.26milliwebers, in cross section of 1/800 m2 = only 1.006 Tesla RMS = 1.42 T peak.
See if you can find a recommended operating flux for that core, or stick with 1T rms..