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berkeman

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What are the specs of the transformer you want to wind on this core? What frequency? What input and output characteristics? What gauge wire(s) do you plan to use for Primary and Secondary?

Are you using the toroidal core for noise reasons? How will you wind the Primary and Secondary? Will they be sector wound, or full-circumfurential (bifilar?)?

- #4

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What are the specs of the transformer you want to wind on this core? What frequency? What input and output characteristics? What gauge wire(s) do you plan to use for Primary and Secondary?

Are you using the toroidal core for noise reasons? How will you wind the Primary and Secondary? Will they be sector wound, or full-circumfurential (bifilar?)?

My line voltage is 230VAC/50Hz I wanted single phase step down transformer to make from this core. But how to determine Core maximum VA capacity. is it 100VA or 200VA how to calculate that. Is Core wet is important in calculating VA .This core is M4 CRGO.Or I have to first wind Primary winding but how to test core maximum VA through that please help.

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anorlunda

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That link has good info on transformer design. Procedures, formulas, data tables.

- #6

berkeman

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Why are you wanting to use a toroidal core for an AC Mains step-down transformer? And what experience do you have working with AC Mains projects? What safety considerations are you keeping in mind in this project? What will the transformer be used for?My line voltage is 230VAC/50Hz I wanted single phase step down transformer to make from this core. But how to determine Core maximum VA capacity. is it 100VA or 200VA how to calculate that. Is Core wet is important in calculating VA .This core is M4 CRGO.Or I have to first wind Primary winding but how to test core maximum VA through that please help.

- #7

jim hardy

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is it 100VA or 200VA how to calculate that.

anorlunda's link looks to me like a good one.

As you read through it

here's the direction you need to be heading -

1. How many turns of wire must you have to in order for your core to support the voltage you want?

That depends on the cross sectional area of the core. I cannot read that test you posted, too blurry and small.

Look for a volts per turn rating.

2. Your toroid has area of X in which you can place those turns of wire.

They call it 'Window Area 'in transformer circles.

What is maximum size wire of which you can physically fit your required number of turns into that area ?

Ampacity of that wire X voltage your core can support is your maximum VA.

- #8

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Why are you wanting to use a toroidal core for an AC Mains step-down transformer? And what experience do you have working with AC Mains projects? What safety considerations are you keeping in mind in this project? What will the transformer be used for?

- Because I wanted to build toroidal transformer.If toroidal core is used Transformer wet is much lower than same VA EI transformer And low humming high efficiency.I make few mains EI transformer and they working good And I lived without any accident. want to use toroidal transformer for amplifier.Can you help me now.

- #9

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That link has good info on transformer design. Procedures, formulas, data tables.

Dear anorlunda This calculation is not for "Toroidal core transformer " that told me when I asked same question to poster of that article.

- #10

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anorlunda's link looks to me like a good one.

As you read through it

here's the direction you need to be heading -

1. How many turns of wire must you have to in order for your core to support the voltage you want?

That depends on the cross sectional area of the core. I cannot read that test you posted, too blurry and small.

Look for a volts per turn rating.

2. Your toroid has area of X in which you can place those turns of wire.

They call it 'Window Area 'in transformer circles.

What is maximum size wire of which you can physically fit your required number of turns into that area ?

Ampacity of that wire X voltage your core can support is your maximum VA.

Dear hardy sir

- You have to zoom that image . This report says 3.30 Turn per volt for 1.5T. suppose we assume 3 turn per volt so 230*3=690 primary turn is required but how to calculate window area of toroidal core and how to chose wire diameter for primary if I chose 0.80A(dimeter-0.67mm,used-750 kcmil/A) supported wire size for primary. Than input VA of transformer is 184VA.Can I use this wire if it fits in Half Window Area of toroidal core without considerations of Core VA capacity.

- #11

jim hardy

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Core VA capacity.

Why do you think the core cares how many VA it is transporting ?

Flux is proportional to magnetizing current not load current.

Its VA capacity is limited by how much wire you can fit through the window. The bigger the core cross section the fewer turns you need.

Can I use this wire if it fits in Half Window Area of toroidal core without considerations of Core VA capacity.

That's your constraint - does it fit ? Will the winding run cool enough ?

I'd go a little under 1.5T not over. Look at the magnetizing currrent !

230 X 3.3 = 759

and do you really have 230 V or closer to 240 ?

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- #12

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Why do you think the core cares how many VA it is transporting ?

Flux is proportional to magnetizing current not load current.

Its VA capacity is limited by how much wire you can fit through the window. The bigger the core cross section the fewer turns you need.

That's your constraint - does it fit ? Will the winding run cool enough ?

I'd go a little under 1.5T not over. Look at the magnetizing currrent !

230 X 3.3 = 759

and do you really have 230 V or closer to 240 ?

Dear Hardy sir

I found following link.They calculate Maximum power handling capacity of toroidal core.as bellow

VA=5.0*J*Bm*f*Ac min*ID²*10-7

where:

VA =Power handling capacity (VA)

J =Current density (A/ mm2)

Bm =Maximum induction ( Tesla)

f =Frequency ( Hz)

ID =Inside diameter (mm)

Ac min =Effective cross sectional area (mm2)

If I enter My core values in that equation result is as follows.

VA= (5.0*3.1*1.5*50*1000*3600)*0.0000001=418.5

Is that means I can make toroidal transformer up to 418 VA.this website has all information about toroidal core calculation.

EILOR MAGNETIC CORES - Calculation Data

- #13

jim hardy

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Is that means I can make toroidal transformer up to 418 VA.

There you go - Well Done !

That's a practical page !

I do a reasonableness check on formulas before i trust them

VA=5.0*J*Bm*f*Ac min*ID²*10-7

VA =Power handling capacity (VA)

J =Current density (A/ mm2)

Bm =Maximum induction ( Tesla)

f =Frequency ( Hz)

ID =Inside diameter (mm)

Ac min =Effective cross sectional area (mm2)

Let's see here

Its VA capacity is limited by how much wire you can fit through the window.

J X ID

Bm X Acmin tells how much flux i can get through the core , which when multiplied by frequency defines the volts per turn

amps X turns X volts/turn = VA

so the form of the equation passes my sanity check.

They collected their constants in those two numbers, 5.0 & 10

and i didnt check them. This is just a sanity check after all .

..

I see where you got every number except the 3.1 for JVA= (5.0*3.1*1.5*50*1000*3600)*0.0000001=418.5

and i got the same result as you when i multiplied

so yes i think your 418.5 VA is the capacity of that core at 3.1 amps/mm

418 VA / 230V = 1.82 amps / 3.1 = 0.59mm2 wire , approximately #19 which seems reasonable

Be aware it might take considerable patience to get enough turns on it when winding by hand instead of using a machine that lays them in neatly

but it's really instructive to wind a core and run a saturation curve on it - plot magnetizing current versus volts per turn.

I'm very much impressed with that Eilor tutorial you found. NIce Job !

Have Fun . We learn 10X better by actually doing things than by just reading about doing them.

Keep us posted ?

old jim

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- #14

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There you go - Well Done !

That's a practical page !

I do a reasonableness check on formulas before i trust them

Let's see here

J X ID^{2}tells how many amps i can get through the window for a given current density, which will define amps X turns

Bm X Acmin tells how much flux i can get through the core , which when multiplied by frequency defines the volts per turn

amps X turns X volts/turn = VA

so the form of the equation passes my sanity check.

They collected their constants in those two numbers, 5.0 & 10^{-7}

and i didnt check them. This is just a sanity check after all .

..

I see where you got every number except the 3.1 for J

and i got the same result as you when i multiplied

so yes i think your 418.5 VA is the capacity of that core at 3.1 amps/mm^{2}

418 VA / 230V = 1.82 amps / 3.1 = 0.59mm2 wire , approximately #19 which seems reasonable

Be aware it might take considerable patience to get enough turns on it when winding by hand instead of using a machine that lays them in neatly

but it's really instructive to wind a core and run a saturation curve on it - plot magnetizing current versus volts per turn.

I'm very much impressed with that Eilor tutorial you found. NIce Job !

Have Fun . We learn 10X better by actually doing things than by just reading about doing them.

Keep us posted ?

old jim

Hello hardy sir

- Thanks for your replay and all your suggestion. This page have one table under power handling capacity in that table current density A/mm2 depend on toroidal core wet. my core wet is 1842 grams according to that table if core wet is under 3500 grams current density should be 3.1A/mm2.
- I found one excel sheet of toroidal transformer winding calculation when i searching Toroidal core on ebay. Can you tell me is this excel sheet is right for calculation of toroidal transformer. https://drive.google.com/file/d/0B5ROBprWe44vTDVfZGFWQjBkMUk/view?usp=sharing

- #15

jim hardy

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How would i know? All i can do is sanity/reasonableness checks on some of the entriesCan you tell me is this excel sheet is right for calculation of toroidal transformer. https://drive.google.com/file/d/0B5ROBprWe44vTDVfZGFWQjBkMUk/view?usp=sharing

Most of the them look reasonable to me

#19 wire is 0.9mm diameter plus insulation

~1mm wire wound around a 6 cm ID circle should be 60π turns, 188 and he got 191 very reasonable

next layer should be a few less turns because ID is smaller and he shows that,

........

1 amp would be 230 watts

i figured about 3 ohms of primary resistance (791 turns at 5 + 5 + 2 + 2 cm per turn = 11 meters X )0.0264 ohm/meter = 2.9Ω )

so i guess his entry for primary length must be centimeters not feet not meters

and the primary resistance enty must be milli-ohms not ohms

that'd be 3 volts of primary drop out of 230 applied, 3/230 = maybe 1.3% which falls between his Excel entries for 100 and 200 watts

So i'd say it passes the sanity/reasonableness check

though it sure would have instilled more initial confidence had he said what were his units

and i wonder what is "final window" ?

Try changing things like wire gage , core thickness, and see if all the numbers move in right direction

That's all i can say from that screenshot.

I'd have wound it based on pencil&paper calculations.

That spreadsheet would give me confidence in them because somebody else got similar result.

old jim

- #16

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How would i know? All i can do is sanity/reasonableness checks on some of the entries

Most of the them look reasonable to me

#19 wire is 0.9mm diameter plus insulation

~1mm wire wound around a 6 cm ID circle should be 60π turns, 188 and he got 191 very reasonable

next layer should be a few less turns because ID is smaller and he shows that,

........

1 amp would be 230 watts

i figured about 3 ohms of primary resistance (791 turns at 5 + 5 + 2 + 2 cm per turn = 11 meters X )0.0264 ohm/meter = 2.9Ω )

so i guess his entry for primary length must be centimeters not feet not meters

and the primary resistance enty must be milli-ohms not ohms

that'd be 3 volts of primary drop out of 230 applied, 3/230 = maybe 1.3% which falls between his Excel entries for 100 and 200 watts

So i'd say it passes the sanity/reasonableness check

though it sure would have instilled more initial confidence had he said what were his units

and i wonder what is "final window" ?

Try changing things like wire gage , core thickness, and see if all the numbers move in right direction

That's all i can say from that screenshot.

I'd have wound it based on pencil&paper calculations.

That spreadsheet would give me confidence in them because somebody else got similar result.

old jim

Hello sir

In that sheet instruction tap have all information about using worksheet "final window" is diameter of the remaining hole in the core center, before any final insulation layer is applied. in millimeters. Is wind transformer about 350VA using that calculation is good in real life.I attach instruction tab information in pdf form bellow.

- #17

jim hardy

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but the calculations are straightforward enough

i see you have to tell the program turns per volt

so it's not doing any magnetic calculations just physical ones to fit your turns into the space available.

It doesn't do any heat calculations either

calculate your I^2R losses at rated power

if they are less than 1 watt per square inch of surface i'd say you're in fine shape(old rule of thumb)

otherwise it might be prudent to up wire by one AWG .

i thought that was a screenshot but i see it's an active spreadsheet out there someplace

old jim

- #18

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but the calculations are straightforward enough

i see you have to tell the program turns per volt

so it's not doing any magnetic calculations just physical ones to fit your turns into the space available.

It doesn't do any heat calculations either

calculate your I^2R losses at rated power

if they are less than 1 watt per square inch of surface i'd say you're in fine shape(old rule of thumb)

otherwise it might be prudent to up wire by one AWG .

i thought that was a screenshot but i see it's an active spreadsheet out there someplace

old jim

Hello Hardy sir

No sir Turn per volt calculate spreadsheet automatically try changing core size value. And Can you tell me what is used of "Power load,W" column. Is for how mush regulation of transformer is given in particularly used VA rating.How to calculate I^2R losses.Tell me if you want this active spreadsheet.

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jim hardy

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i dont know how to make it go. But that is to me amazing ... Handy program to know about!No sir Turn per volt calculate spreadsheet automatically try changing core size value.

And Can you tell me what is used of "Power load,W" column.

Hmm it's green, so you had to type them in ?

I'd guess the program figures regulation at those points. ame as you proposed

Is for how mush regulation of transformer i think so

is given in particularly used VA rating. i dont know what you mean by that

How to calculate I^2R losses. i estimated simply by resistance of the winding X square of current at selected VA. At the time i didnt know he'd given resistance in milliohms so estimated from a wire table and my own estimated length so i probably differed slightly from his numbers.

Will you be winding that transformer soon ? Keep us posted !

old jim

- #20

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Finally Done primary winding today of my toroidal core.Attach photo of transformer below.

755 turn of 0.914 mm magnet wire.

core size before winding OD-100mm, ID-60mm, Ht-50mm (M4,CRGO) as we discuss early.

Sir when I test for secondary voltage I get 2.7 volt on 10 turn of magnet wire . why I get less volt per turn. Because before full primary winding when I wind 10 turn for testing perpose on core I get 3.2 volt.Please replay soon

- #21

jim hardy

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230 volts across 755 turn primary = 0.305 volts per turnFinally Done primary winding today of my toroidal core.Attach photo of transformer below.

755 turn of 0.914 mm magnet wire.

That's how much flux is in your core and that's what it will induce into secondary.

Do you have a slider transformer(Variac) ?

The .27 volts per turn you measured sounds about right

try swapping your volt meter leads, the one turn they complete might explain the 10% difference between .27 and .305

old jim

- #22

jim hardy

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Because before full primary winding when I wind 10 turn for testing perpose on core I get 3.2 volt.Please replay soon

Ahh i missed that part , you tested it with a partial primary .....

How many turns were on your primary when you made that partial test ? Sounds like you had a lot fewer.

Volts per turn is the key to understanding what goes on in a core, it's a measure of induction (amount of flux)

The fewer primary turns, the more volts per turn

so when you tested with a partial primary, what was the turns ratio?

Very nice looking job in the pictures, by the way.... Will you tape it when through? Or dip in varnish ?

- #23

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230 volts across 755 turn primary = 0.305 volts per turn

That's how much flux is in your core and that's what it will induce into secondary.

Do you have a slider transformer(Variac) ?

The .27 volts per turn you measured sounds about right

try swapping your volt meter leads, the one turn they complete might explain the 10% difference between .27 and .305

old jim

Thanks Hardy sir

What is slider transformer its sound veritable voltage transformer please clear for me. why in secondary drooping volt per turn

- #24

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Ahh i missed that part , you tested it with a partial primary .....

How many turns were on your primary when you made that partial test ? Sounds like you had a lot fewer.

Volts per turn is the key to understanding what goes on in a core, it's a measure of induction (amount of flux)

The fewer primary turns, the more volts per turn

so when you tested with a partial primary, what was the turns ratio?

Very nice looking job in the pictures, by the way.... Will you tape it when through? Or dip in varnish ?

hardy sir

I tested with my other transformer who have 12 volt secondary make input supply for this partial test 37 primary turn and 20 secondary turn i get 6.4 to 6.5 volt in output.

I dint use any tape or varnish but simple cotton tape without any adhesive. wrap cardboard first on bare core and apply cotton tapes tightly over on cardboard Than wind primary turn. Can it is OK to use cotton tapes.How to measure of induction (amount flux) of core.

- #25

jim hardy

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Yes, they're also known as "Variac" but hat's a trademarkWhat is slider transformer its sound veritable voltage transformer

Staco makes them too

clear for me. why in secondary drooping volt per turn

A transformer has a turns ratio

Vsecondary / Vprimary = Turns secondary / Turns primary

so Vsecondary/Turns secondary = Vprimary /Turns primary

volts per turn is same both sides

when you add turns to primary and appply same voltage(230?) you reduce volts per turn on both

12 X 20 / 37 = 6.49, it's working just right !I tested with my other transformer who have 12 volt secondary make input supply for this partial test 37 primary turn and 20 secondary turn i get 6.4 to 6.5 volt in output.

- #26

jim hardy

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How to measure of induction (amount flux) of core.

try this approach

volts per turn is a good measure

e = n dΦ/dt

if Φ = A sin(100πt)

dΦ/dt = 100πAcos(100t)

so e = n

you know n = 755

and e = 230√2 cos(100t)

so A = 230√2cos(100t) / (755 X 100πcos(100t))

A = .00137 Webers

did i make any arithmetic mistakes? Took me several tries to get same answer twice in a row.. darn that Windows calculator

divide Webers by area of core in square meters to get Teslas

volts per turn divided by ω gets magnitude of flux,

0..305 / 100π = .000971 Weber RMS flux, which is .00137 peak, divide them by area of core to get flux density

volts per turn at your line frequency is a handy thing to know about a core.

Now - what do you get for your flux density ?

- #27

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Yes, they're also known as "Variac" but hat's a trademark

Staco makes them too

A transformer has a turns ratio

Vsecondary / Vprimary = Turns secondary / Turns primary

so Vsecondary/Turns secondary = Vprimary /Turns primary

volts per turn is same both sides

when you add turns to primary and appply same voltage(230?) you reduce volts per turn on both

12 X 20 / 37 = 6.49, it's working just right !

So hardy sir

to get 70 volt 230*232/755=70.67 volt

But Actually after I finish primary winding. try finding secondary turn per volt wind 10 turn for testing i get 2.7 volt means 0.27 volt per turn so to get 70 volt 70/0.27=

- #28

jim hardy

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place 1 turn around the core, make it from just your meter leads

see wnether you get 0.27 or 0.30 volts, write down result

then see which is closer - 232 or 259

then wind 232 turns but don't cut your wire, leave enough for 27 more turns (i'd leave enough for 40 or 50 more and measure voltage

if you come up short of volts keep adding turns until it's where you want it

what flux density did you find ?

see wnether you get 0.27 or 0.30 volts, write down result

then see which is closer - 232 or 259

then wind 232 turns but don't cut your wire, leave enough for 27 more turns (i'd leave enough for 40 or 50 more and measure voltage

if you come up short of volts keep adding turns until it's where you want it

what flux density did you find ?

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- #29

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place 1 turn around the core, make it from just your meter leads

see wnether you get 0.27 or 0.30 volts, write down result

theb see which is closer - 232 or 259

then wind 232 turns but don't cut your wire, leave enough for 27 more turns (i'd leave enough for 40 or 50 more and measure voltage

if you come up short of volts keep adding turns until it's where you want it

what flux density did you find ?

Hello sir

0.00137*0. 001=1.37 is it right

Can I get multi pal voltage on same secondary winding how to do it

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- #30

jim hardy

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multiple ?Can I get multi pal voltage on same secondary winding how to do it

tapped windings are done all the time

Just

That loop becomes a tap.

http://www.bing.com/videos/search?q...8EEA92C1EEA1ECB69D6B8EEA92C1EEA1E&FORM=VRDGAR

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