How to Calculate Watt: Understanding the Basics

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The discussion revolves around calculating wattage using a car's acceleration and work done. The user initially misapplies the formula for work, mistakenly using mass times acceleration squared instead of the correct kinetic energy formula. After receiving guidance, they correctly calculate the change in kinetic energy and determine the work done. The final calculation yields a power output of approximately 53 kW, which the user finds reasonable. The conversation highlights the importance of understanding the correct formulas in physics calculations.
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ive always been interested in calculations, so i want to try to calculate watt but I am stuck

bear in mind this is a pure hobby for me and i am far from a math genious



in this example i use a car

here is how far i have come

it accelerates from 22.2m/s to 33.3 m/s in 7 seconds
to calculate acceleration you do like this

highest speed-lowest/time 33.3-22.2=11.1 11.1/7 is almost 1.58

giving the car acceleration of 1.58m/s^2 so far so good
-----------------------------------------------------------

next is calculating work
work= mass*acceleration^2

so if the car is 1200kg(Newton)

then we take 1200* (1.58*1.58) = 2996 joules (this is correct i hope)
--------------------------------------------------------------------------

and this is where i get stuck because the formulas i find state that watt=work/time

2996joules/7sec is obviously wrong...



can anybody help me?

cheers/Johan
 
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skaunejohan said:
in this example i use a car

here is how far i have come

it accelerates from 22.2m/s to 33.3 m/s in 7 seconds
to calculate acceleration you do like this

highest speed-lowest/time 33.3-22.2=11.1 11.1/7 is almost 1.58

giving the car acceleration of 1.58m/s so far so good
OK, that's the average acceleration. The units should be m/s², not m/s. (But you don't really need the acceleration to find the work done.)
-----------------------------------------------------------

next is calculating work
work= mass*acceleration^2
This is incorrect. (Note that that quantity does not have the correct units for work/energy.)

To calculate the work done, find the change in kinetic energy. Kinetic energy = ½mv².
 
skaunejohan said:
ive always been interested in calculations, so i want to try to calculate watt but I am stuck

bear in mind this is a pure hobby for me and i am far from a math genious



in this example i use a car

here is how far i have come

it accelerates from 22.2m/s to 33.3 m/s in 7 seconds
to calculate acceleration you do like this

highest speed-lowest/time 33.3-22.2=11.1 11.1/7 is almost 1.58

giving the car acceleration of 1.58m/s so far so good
-----------------------------------------------------------

next is calculating work
work= mass*acceleration^2

so if the car is 1200kg(Newton)

then we take 1200* (1.58*1.58) = 2996 joules (this is correct i hope)
--------------------------------------------------------------------------

and this is where i get stuck because the formulas i find state that watt=work/time

2996joules/7sec is obviously wrong...



can anybody help me?

cheers/Johan

A couple issues. First the acceleration would be 1.58m/s^2. Velocity has units of m/s and acceleration has units of m/s^2.

Next, I do not think this is correct: "work= mass*acceleration^2" Where did you get that?

Force = mass*acceleration (F=ma), and work = Force*distance.

Does that help?
 
Doc Al said:
OK, that's the average acceleration. The units should be m/s², not m/s. (But you don't really need the acceleration to find the work done.)

This is incorrect. (Note that that quantity does not have the correct units for work/energy.)

To calculate the work done, find the change in kinetic energy. Kinetic energy = ½mv².


sorry my mistake, like i stated above I am only doing this as a hobby, i will alter the acceleration immediatley

thanks for the fast reply, I am sorry but i have no idea how to calculate the kinetic energy can you help me?
 
berkeman said:
A couple issues. First the acceleration would be 1.58m/s^2. Velocity has units of m/s and acceleration has units of m/s^2.

Next, I do not think this is correct: "work= mass*acceleration^2" Where did you get that?

Force = mass*acceleration (F=ma), and work = Force*distance.

Does that help?

ahh now i see one of the problems in my calculation

it stated work=N*m/s^2



so force should be 1200*1.58? (1896watt?)





is it possible to calculate distance from the starting speed of 22.2m/s and finish speed of 33.3m/s over 7sec

sounds over-complicated...

thanks for the fast reply
 
skaunejohan said:
im sorry but i have no idea how to calculate the kinetic energy can you help me?

Doc Al said:
Kinetic energy = ½mv².
You have the mass (m) and the speed (v). Calculate the initial and final kinetic energy, then find the change.
 
Doc Al said:
You have the mass (m) and the speed (v). Calculate the initial and final kinetic energy, then find the change.

ahhh :)

starting kinetic 0,5*1200*(22.2*22.2)= 295704 joules

ending kinetic 0.5*1200*(33.3*33.3)= 665334 joules

369630 joules

(just thinking loud now)
369.6/7=53kw sounds very reasonable as a medium power

is it really that simple?

cheers/Johan
 
Yes, it's that simple.
 
thanks a lot :) this forum is great!
 
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