How to Choose Eigenvectors for Diagonalization

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When diagonalizing a matrix, the order of the eigenvectors in matrix P determines the arrangement of the corresponding eigenvalues in the diagonal matrix. In the given example, the eigenvalues are 4, 2, and 1, and the diagonal matrix will reflect this order based on how the eigenvectors are placed in P. Changing the order of the eigenvectors in P will result in a different arrangement of eigenvalues in the diagonal matrix. The diagonal matrix itself is not the same as matrix P; it is formed from the eigenvalues. Understanding this relationship is crucial for correctly diagonalizing a matrix.
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This isn't really a homework question, but it is relevant to heling me finish my homework.
When you are diagonalizing a matrix, how do you know what order to put the eigenvectors in.
One of my homework problems is with the eigenvalues 1, 2, and 4.
[-1]
[1] is the matrix corresponding to the eigenvalue 1.
[1]

[1]
[0] is the matrix corresponding to the eigenvalue 2
[0]

[7]
[-4] is the matrix corresponding to the eigenvalue 4.
[1]

The answers in the back of the book give the diagonalized matrix as
[7 1 -1]
[-4 0 1]
[2 0 1]
 
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rtw528 said:
This isn't really a homework question, but it is relevant to heling me finish my homework.
When you are diagonalizing a matrix, how do you know what order to put the eigenvectors in.
One of my homework problems is with the eigenvalues 1, 2, and 4.
[-1]
[1] is the matrix corresponding to the eigenvalue 1.
[1]

[1]
[0] is the matrix corresponding to the eigenvalue 2
[0]

[7]
[-4] is the matrix corresponding to the eigenvalue 4.
[1]

The answers in the back of the book give the diagonalized matrix as
[7 1 -1]
[-4 0 1]
[2 0 1]

The matrix above is NOT the diagonal matrix - it is the matrix P, the one with the eigenvectors as columns. The order in which you put the eigenvectors doesn't matter except that it affects how the eigenvalues will appear in the diagonal matrix.

For your example, the columns in P correspond to the eigenvalues 4, 2, and 1, respectively. The diagonal matrix will be
$$ \begin{bmatrix} 4 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 1\end{bmatrix}$$
 
If the eigenvalues are \lambda_1 with eigenvector v_1, \lambda_2 with eigenvector v_2, and \lambda_3 with eigenvector v_3, then the order in which you use the vectors as columns in matrix "P" will determine the order of the eigenvalues in the diagonal matrix.

That is, if P have columns v_1, v_2, v_3, in that order, then the diagonal matrix will be
\begin{bmatrix}\lambda_1 & 0 & 0 \\ 0 & \lambda_2 & 0 \\ 0 & 0 & \lambda_3\end{bmatrix}
changing the columns in P changes the order in the diagonal matrix.

For example, if P have columns v_2, v_1, v_3, in that order, then the diagonal matrix will be
\begin{bmatrix}\lambda_2 & 0 & 0 \\ 0 & \lambda_1 & 0 \\ 0 & 0 & \lambda_3\end{bmatrix}
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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