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Joelly
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MHB How to Choose the Right Running Shoes for You
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HOI
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Are you taking an "Abstract Algebra". If so you should know what "isomorphic" means- that there is a function from one group to the other, f: G->H, that
1) it is "one-to-one"- if f(x)= f(y) the x= y.
2) it is "onto"- for every y in H there exist x in G such that f(x)= y.
3) it "preserves the operation"- f(x+ y)= f(x)+f(y).
G is defined as multiples of 2 and H is defined as multiples of 3. What about f(2n)= 3n?
1) it is "one-to-one"- if f(x)= f(y) the x= y.
2) it is "onto"- for every y in H there exist x in G such that f(x)= y.
3) it "preserves the operation"- f(x+ y)= f(x)+f(y).
G is defined as multiples of 2 and H is defined as multiples of 3. What about f(2n)= 3n?
Hello!
In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way:
I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true?
And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...