How to compute the area of a hyperboloid of revolution?

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SUMMARY

The surface area of a one-sheeted hyperboloid can be computed using the implicit equation (x/a)² + (y/a)² - (z/c)² = 1. To parametrize the surface, use the equations x = a*cos(u)*cosh(v), y = a*sin(u)*cosh(v), and z = c*sinh(v), where u ranges from 0 to 2π. The limits for v are determined by the limits of z. The resulting surface integral is analytically solvable, providing a definitive method for calculating the area.

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DaviesX
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Assume that the implicit equation of the one-sheeted hyperboloid is
(x/a)^2 + (y/a)^2 - (z/c)^2 = 1

How am I able to obtain the surface area of hyperboloid ?
Thanks
 
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Parametrize the surface by:
x=a*cos(u)*cosh(v)
y=a*sin(u)*cosh(v)
z=c*sinh(v)

Where u runs the from 0 to 2*pi, whereas the limits of v is determined by the limits of z.

Then, set up the surface integral in the usual way; it is analytically solvable.
 
Last edited:
Thank you. I'll try it
 

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