# How to compute the area of a hyperboloid of revolution?

1. Aug 4, 2012

### DaviesX

Assume that the implicit equation of the one-sheeted hyperboloid is
(x/a)^2 + (y/a)^2 - (z/c)^2 = 1

How am I able to obtain the surface area of hyperboloid ?
Thanks

2. Aug 4, 2012

### arildno

Parametrize the surface by:
x=a*cos(u)*cosh(v)
y=a*sin(u)*cosh(v)
z=c*sinh(v)

Where u runs the from 0 to 2*pi, whereas the limits of v is determined by the limits of z.

Then, set up the surface integral in the usual way; it is analytically solvable.

Last edited: Aug 4, 2012
3. Aug 4, 2012

### DaviesX

Thank you. I'll try it