How to Compute the Inertia Tensor of a Cross-Hanger?

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SUMMARY

The discussion focuses on computing the inertia tensor of a cross-hanger made of three thin, linear wires, each with mass M and length L, arranged perpendicularly at the origin (0,0,0). The inertia tensor is defined using the formula I_{ij}=\int\rho(\delta_{ij}\sum_{k}x_{k}^{2}-x_{i}x_{j})dV, with specific calculations for I_{11} involving the integration of x_{2}^{2} and x_{3}^{2}. The challenge lies in determining the appropriate limits for integration due to the unique geometry of the cross-hanger, as opposed to simpler shapes like cubes.

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I've done many exercises about inertia tensors of 3D bodies and sticks but now I have this exercise and I got stuck without any idea of how to do the integration to compute the inertia tensor. The statement is this:

"Compute the inertia tensor of a cross-hanger consisting of 3 thin and linear wires, with mass M and length L, glued perpendicularly by their central parts which is placed at (x,y,z)=(0,0,0)."​

As you know, the inertia tensor (or matrix) for an homogeneous body is constructed from

I_{ij}=\int\rho(\delta_{ij}\sum_{k}x_{k}^{2}-x_{i}x_{j})dV

So that, for example,

I_{11}=\int\rho(x_{2}^{2}+x_{3}^{2})dV

If it was a cube for example we could integrate the expression effortlessly with the integral limits in the 3 variables going from -L/2 to L/2. But with this shape I'm not sure how to do it. Can you help me with the integration? Should I fix one variable at 0 and integrate the others?
 
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The inertia tensor of a body that consists of multiple parts is the sum of the inertia tensors of the parts.
 

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