How to Convert 938.3 MeV/c² to Kilograms?

[cragar]

Homework Statement

how do i convert 938.3MeV/(c^2) to kilo grams

The Attempt at a Solution

so this is mega electron volts divided by c^2 do i just divide it by 1.602*10^(-19) joules
is e measured in coulombs and a volt is a joule per coulomb.

 

[magwas]

The eV is a measure of energy, equalling somewhere about 1.6 * 10^(-19) J
1 J = 1 kg * m^2/s^2
I assume c wants to be the speed of the light, which is given in m/s

so 1 eV/c^2= (some scalar) * kg * m^2/s^2 / (m/s)^2
now what you get by simplifying?

It always helps not to forget to write the units, and go for base units when in doubt.

 

[cragar]

thanks , ok i see , so i multiply it by 1.602*10^(-19)J/1eV to get it Kg .
correct