We know that we can create an electron-positron pair out of a gamma-ray, if it has an energy of [tex]E=h\nu>2m_ec^2[/tex].(adsbygoogle = window.adsbygoogle || []).push({});

However a photon is described as an EM-wave that obeys the divergence criteria

[tex]\nabla\cdot\vec{E}=0[/tex]

My question is simply if there is a "simple" explanation out there (QFT?) which describes microscopically what happens when the photon breaks up and 2 charged packages are created? I also wonder what the distance between the particles is in the creation moment.

My guess is that the EM-wave/photon must be disturbed in some way (by gravity?) such that it bends in some way, and that it is this bending which gives rise to the charge creation: [tex]\nabla\cdot\vec{E}=\rho/\epsilon[/tex], but where the total charge is neutral, like in the point-particle classical situation:

[tex]\rho=e(\delta(r-a)-\delta(r+a))[/tex] (some kind of dipole, but perhaps rater described with waves)

Any idea?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# How to create charge from light?

**Physics Forums | Science Articles, Homework Help, Discussion**