We know that we can create an electron-positron pair out of a gamma-ray, if it has an energy of [tex]E=h\nu>2m_ec^2[/tex].(adsbygoogle = window.adsbygoogle || []).push({});

However a photon is described as an EM-wave that obeys the divergence criteria

[tex]\nabla\cdot\vec{E}=0[/tex]

My question is simply if there is a "simple" explanation out there (QFT?) which describes microscopically what happens when the photon breaks up and 2 charged packages are created? I also wonder what the distance between the particles is in the creation moment.

My guess is that the EM-wave/photon must be disturbed in some way (by gravity?) such that it bends in some way, and that it is this bending which gives rise to the charge creation: [tex]\nabla\cdot\vec{E}=\rho/\epsilon[/tex], but where the total charge is neutral, like in the point-particle classical situation:

[tex]\rho=e(\delta(r-a)-\delta(r+a))[/tex] (some kind of dipole, but perhaps rater described with waves)

Any idea?

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# How to create charge from light?

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