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How to derive continuity eqn. in polar form?

  1. Jan 11, 2007 #1
    plzzzzzzzzzzzzzzzzz
     
  2. jcsd
  3. Jan 27, 2007 #2
    You know that the continuity equation states out - in + change = 0
    Therefore draw a small control colume with dimensions Theta * R, Theta * (R + dR). dR, dZ (looks like piece of pie with the point taken out.
    The simply see flow going in on on side out on the other and the difference is the change, dRho/dt * R*dR*dTheta*dz
    just to help you out:
     
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