How to Derive Power for a Drone Hovering Using a Capacitor?

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To derive the power required for a drone to hover, the formula used is mgv/2, where m is the mass, g is gravitational acceleration, and v is the air velocity. For a 20-gram drone generating lift at an air flow velocity of 2 m/s, the power calculation is based on the energy stored in a 1 F capacitor charged at 10 volts. The discussion emphasizes the need for understanding the relationship between power, work, and force in the context of drone flight. Participants are encouraged to attempt solving the problem independently before seeking assistance. The conversation highlights the importance of how propeller blades interact with air to generate necessary lift.
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A 1 F capacitor is charged at 10 Volt and powers a small copter drone of m=20 grams.
The copter generates a vertical lift to balance gravity. It does this with a
propeller than pushes air downward at a velocity v. Show that the power required
is mgv/2. At an air flow velocity of 2 m/s , calculate how long the copter stays up
(assuming 100% energy efficiency and controlling the power distribution to be
steady).
 
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Chris Johns said:
A 1 F capacitor is charged at 10 Volt and powers a small copter drone of m=20 grams.
The copter generates a vertical lift to balance gravity. It does this with a
propeller than pushes air downward at a velocity v. Show that the power required
is mgv/2. At an air flow velocity of 2 m/s , calculate how long the copter stays up
(assuming 100% energy efficiency and controlling the power distribution to be
steady).

PF rules require some effort on your part. Try solving the problem for yourself, and if you are stuck on some issue, come back here and explain the difficulty. Maybe then you can be receive help.
 
I've been trying for a week now! I know that
Power = rateOfDoingWork

Work = Force * Distance = mass * g * Distance

Power = d/dt (Work) = d/dt (Force * Distance) = d/dt (Force)* Distance + d/dt (Distance) * Force

also d/dt(Force) goes to zero because mass (m) is constant and gravitational acceleration (g) is constant.

Thus Power = m * g * v

But I can't go any further than this. I would greatly appreciate any help.
 
For the blades to generate a force what must they do to the air?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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