How to determine if a set is an open subset of a Euclidean space?

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SUMMARY

The discussion centers on determining if a set is an open subset of a Euclidean space, specifically using the example of the set defined by the inequality {(x,y) ∈ R² | x² + y² < 1}. This set represents the interior of the unit circle, illustrating that for any point within this set, one can move in any direction without leaving the set. The concept of open balls is introduced, emphasizing that a set is open if it contains a neighborhood around each of its points. The discussion concludes with a question about the necessity of proving the set's openness.

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  • Understanding of Euclidean spaces and their properties
  • Familiarity with inequalities and their geometric interpretations
  • Knowledge of open sets and open balls in topology
  • Basic concepts of limits and continuity in mathematical analysis
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  • Study the definition and properties of open sets in topology
  • Learn about open balls and their role in defining open subsets
  • Explore the concept of boundary points and their significance in set theory
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kelp
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I opted to not use the template because this is a pretty general question. I am not understanding how to find out if a set is an open subset of a Euclidean space.
For example,
{(x,y) belongs R2 | x squared + y squared < 1}
The textbook is talking about open balls, greatly confusing me.
 
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Intuitively speaking, a set is open if you can take any point in the set, move a little distance in any direction and still be in the set. In this situation, the set of points (x,y) such that x^2 + y^2 < 1 is really the "inside" of a circle of radius one (specifically we are dealing with the unit circle). If your point is near the center of the circle, it is obvious that you can move some distance away and still remain inside the circle. But the idea is that if we have a point near the "edge" or the boundary of the circle, we can still move closer and closer towards the edge without hitting the boundary, and this is why we have the inequality x^2 + y^2 < 1 (when < is replaced with =, we are on the unit circle). Does this make sense?

Hmm so I guess I gave away the answer but not really. Do you need to prove the set is open?
 

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