How to determine the volume of water to add to a dried primer

[ver_mathstats]

Homework Statement

A volume of highly purified water is added to dried primer to create 100uM stock solution. How many ul of water needs to be added to 26.6nMoles of dried primer in order to create uM stock solution? Hint: You may need to convert primer value from nMoles to uMoles.

Homework Equations

The Attempt at a Solution

I know that 26.6nMoles is 0.0266uMoles. But I am unsure of what to do next. Must I use C₁V₁=C₂V₂? Or does 10 x 26.6 = 266ul work?

 

[mjc123]

Or does 10 x 26.6 = 266ul work?

Work for what?

I know that 26.6nMoles is 0.0266uMoles

OK, so if you dissolved it in 1L the concentration would be 0.0266 µM. You want 100 µM. This is where you apply C₁V₁ = C₂V₂.

 

[ver_mathstats]

Work for what?

OK, so if you dissolved it in 1L the concentration would be 0.0266 µM. You want 100 µM. This is where you apply C₁V₁ = C₂V₂.

Oh okay, I think the formula is c=n/v. Thank you.