How to determine the volume of a region bounded by planes?

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Homework Help Overview

The problem involves determining the volume of a region bounded by specific planes in three-dimensional space, specifically the planes x=0, y=0, z=0, x+y=1, and z=x+y. The context includes finding the volume through integration and considering the center of mass for a solid of uniform density.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting up a triple integral for volume calculation and express uncertainty about determining the limits of integration. There are suggestions to visualize the region through sketches to aid in understanding the boundaries.

Discussion Status

Some participants have confirmed the proposed boundaries for the integration, indicating a productive direction in the discussion. However, there is still exploration regarding the best methods to define these boundaries and the overall setup for the integration.

Contextual Notes

Participants are considering the implications of drawing sketches to clarify the problem setup and boundaries, which may influence their approach to the integration process.

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Homework Statement


Let G be the region bounded by the planes x=0,y=0,z=0,x+y=1and z=x+y.

Homework Equations



(a) Find the volume of G by integration.
(b) If the region is a solid of uniform density, use triple integration to find its center of mass.

The Attempt at a Solution


[/B]
My understanding is that I need to setup a triple integral:

∫∫∫dxdydz

I’m just a little unsure about how to determine the terminals
 
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Did you draw a sketch?

You can always find boundaries for e.g. z as function of x,y and boundaries for y as function x, but sometimes there are easier methods.
 
Have you drawn a picture? That's the first step. Maybe this will help:
object.jpg
 

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mfb said:
Did you draw a sketch?

You can always find boundaries for e.g. z as function of x,y and boundaries for y as function x, but sometimes there are easier methods.
So would the boundaries be:

0≤z≤x+y
0≤y≤1-x
0≤x≤1
 
That will work.
 

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