How to do a double integral on matlab?

[Lucas94]

Hey! I want to do a double integral calculation of this problem$∫∫ xy/(xy^2 +1)^2$

over the region bounded by 2 ≤ x ≤ 3 and 2*sqrt(1+x) ≤ y ≤ 2*sqrt(2+4x)
on MATLAB and i have tried the following syntax:

clc

clear all

fun=@(x,y) x*y./((x*y.^2+1).^2);

ymax=@(x) 2*sqrt(2+4*x);
q=integral2(fun,2,3,2*sqrt(1+x),ymax);But its doesn't work, can someone see what I am doing wrong?

 

[SteamKing]

Hey! I want to do a doubble integral calculation on MATLAB and i have tried the following syntax:

clc

clear all

fun=@(x,y) x*y./((x*y.^2+1).^2);

ymax=@(x) 2*sqrt(2+4*x);
q=integral2(fun,2,3,2*sqrt(1+x),ymax);But its doesn't work, can someone see what I am doing wrong?

It's not clear which double (only one 'b' in double) integral you are trying to evaluate.

If you would provide the actual integral using calculus notation, that would be a big help. Also, specify the region of integration or the limits, as required.

 

[Lucas94]

It's not clear which double (only one 'b' in double) integral you are trying to evaluate.

If you would provide the actual integral using calculus notation, that would be a big help. Also, specify the region of integration or the limits, as required.

$∫ ∫ xy/(xy^2 +1)^2$

over the region bounded by 2 ≤ x ≤ 3 and 2*sqrt(1+x) ≤ y ≤ 2*sqrt(2+4x)

 

[SteamKing]

$∫ ∫ xy/(xy^2 +1)$

over the region bounded by 2 ≤ x ≤ 3 and 2*sqrt(1+x) ≤ y ≤ 2*sqrt(2+4x)

The denominator of the integrand above is (xy² + 1)

clc

clear all

fun=@(x,y) x*y./((x*y.^2+1).^2);

ymax=@(x) 2*sqrt(2+4*x);

In the definition fun above, the denominator appears to be (xy² + 1)². See the difference?

 

[Lucas94]

The denominator of the integrand above is (xy² + 1)
In the definition fun above, the denominator appears to be (xy² + 1)². See the difference?

My bad i forgot to write it on the integrand , the denominator should be $(xy^2 + 1)^2$ soo my definition of fun is correct