How to draw a 2D space in 3D Euclidean space by metric tensor

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SUMMARY

This discussion focuses on the process of embedding a 2D space, characterized by a given metric tensor, into 3D Euclidean space. The example provided is the metric tensor of a sphere of radius R, represented as gij = \begin{pmatrix} R^2 & 0 \\ 0 & R^2\cdot sin^2\theta \end{pmatrix}. It is established that not all 2D manifolds can be isometrically embedded in 3D space, and when they can, the solutions may not be unique due to the presence of intrinsic (Gauss curvature) and extrinsic (mean curvature) properties. The embedding is described mathematically by the equation gij = ∂i𝑠(u, v) ⋅ ∂j𝑠(u,v), where 𝑠(u,v) is a vector in R3.

PREREQUISITES
  • Understanding of metric tensors, specifically in the context of differential geometry.
  • Familiarity with concepts of intrinsic and extrinsic curvature.
  • Knowledge of nonlinear differential equations and their solutions.
  • Basic understanding of 3D Euclidean space and its properties.
NEXT STEPS
  • Study the properties of Gauss curvature and mean curvature in differential geometry.
  • Explore the theory of isometric embeddings and their applications in geometry.
  • Learn about nonlinear differential equations and techniques for solving them.
  • Investigate specific examples of 2D surfaces and their embeddings in 3D space.
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Mathematicians, physicists, and computer graphics professionals interested in the geometric representation of surfaces and the mathematical foundations of embedding theories.

arpon
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Suppose, I know the metric tensor of a 2D space. for example, the metric tensor of a sphere of radius R,
gij = ##\begin{pmatrix} R^2 & 0 \\ 0 & R^2\cdot sin^2\theta \end{pmatrix}##
,and I just know the metric tensor, but don't know that it is of a sphere.
Now I want to draw a 2D space(surface) which will have the metric tensor gij and will be embedded on 3D Euclidean space.
 
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Your question does not always have an answer! Not every 2d manifold is isometrically embeddable into 3d Euclidean space.

When your question does have an answer, it might not be unique. For example, the metric

$$ds^2 = dx^2 + dy^2$$
could be an infinite plane, or it could be a cylinder, or it could be a non-circular cylinder, or it could be an infinite plane with a plane wave wiggle on it of arbitrary profile.

In general, you have a whole arbitrary function's worth of non-uniqueness for isometric embeddings into R^3. The reason for this is that surfaces embedded in R^3 have two curvatures: an intrinsic one (Gauss curvature) and an extrinsic one (mean curvature). As the terminology would imply, only the Gauss curvature is determined by the 2d metric tensor; the mean curvature is a property of the choice of embedding.

In general, you should write

$$g_{ij} = \partial_i \vec s(u, v) \cdot \partial_j \vec s(u,v)$$
where ##g_{ij}## is your 2d metric tensor, ##u, v## are your 2d coordinates, and ##\vec s(u,v)## is a vector (in R^3) describing your surface, as a function of ##u,v##. Your task is to solve these equations for ##\vec s##. You have a coupled set of nonlinear differential equations. It is not always easy to find solutions.
 
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