How to draw the function x+5<7

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Manula
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I am just interested in knowing, how to draw the function x+5<7 in a cartesian plane.
Since the definition of a function is, If For a certain input, there exist an out, then it is a function.
Is x+5<7 is a valid function then?
 
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If the inequality has only one variable (as yours does), you would graph the solution on a number line. If the inequality has two variables (x and y), then you could graph the solution on a Cartesian plane.
 
To draw a graph of this inequality, first draw the graph of the corresponding equation. x+ 5= 7. That. of course, is the same as "x= 2". It's graph, in a two dimensional "xy" graph, is the vertical line at x= 2. The set of points for which x+ 5< 7 is the set of points for which x< 2. That is, all points to the left of that vertical line.
 
HallsofIvy said:
To draw a graph of this inequality, first draw the graph of the corresponding equation. x+ 5= 7. That. of course, is the same as "x= 2". It's graph, in a two dimensional "xy" graph, is the vertical line at x= 2. The set of points for which x+ 5< 7 is the set of points for which x< 2. That is, all points to the left of that vertical line.

But if we take y=(x+5) and then, draw the graph, wouldn't it give different results??
 
Manula said:
But if we take y=(x+5) and then, draw the graph, wouldn't it give different results??

True.
Of the simple reason that the first inequality does not place any sort of restrictions on the y-coordinate in the points' (x,y) coordinate pairs.