How to Eliminate the Parameter in a Set of Parametric Equations?

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Homework Help Overview

The discussion revolves around eliminating the parameter from a set of parametric equations defined as x = e^t + e^-t and y = e^t - e^-t. Participants are exploring methods to express these equations without the parameter t.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss squaring the equations for x and y, leading to expressions involving e^2t and e^-2t. There is a suggestion to manipulate these squared equations to find a relationship between x and y. Some participants express uncertainty about the implications of their findings, particularly regarding the signs of y.

Discussion Status

The discussion is active, with participants providing guidance on manipulating the equations. There is a recognition of a potential relationship between x and y, specifically x^2 - y^2 = 4, although some participants express uncertainty about the need to solve for x or y explicitly.

Contextual Notes

Participants question the assumptions regarding the range of y and the domain of t, indicating a lack of clarity on these constraints. There is also a mention of checking answers against a textbook, suggesting that external validation is being considered.

jcook735
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Express the set of parametric equations x = E^t + e^-t and y = e^t - e^-t without using the parameter t.


I really have no idea how to do this one. I tried substituting, and it just turned into a jumbled mess of nothing. Please help
 
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did you try squaring the x and the y equations ?
 
well I got x^2 = e^2t + 2 + e^-2t and y^2 = e^2t - 2 + e^-2t but I don't know where to go from there
 
if you move the 2's to the other side, your right hand sides are basically equal.
 
OH! Thanks! So if I understand correctly, ill move the twos over and get the right sides to be the same and x^2 - 2 and y^2 +2. Then I should set these two equal to each other and find y, which comes out to be (plus or minus) the square root of x^2 - 4?
 
jcook735 said:
OH! Thanks! So if I understand correctly, ill move the twos over and get the right sides to be the same and x^2 - 2 and y^2 +2. Then I should set these two equal to each other and find y, which comes out to be (plus or minus) the square root of x^2 - 4?

I think you need to take only the 'plus', because if I'm not mistaken, Y can't be negative according to the parametric equations.
So the range is Y=>0.
I am not really sure about this.
even if 't' is negative (do you have the domain of t ?), these equations can never be negative (neither the X nor the Y).
again, I am not really sure about this.

can you check the answers in the book ?
 
Yes, x^2-y^2=4. If that's what you mean. There's no need to solve for x or y is you just want to eliminate the parameter.
 

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