How to Evaluate Difficult Double Integrals with Limits in the Range of 0 to 1?

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Discussion Overview

The discussion revolves around evaluating the double integral ∫∫xexp(xy)dA over the region defined by the limits 0 to 1 for both x and y. Participants are seeking clarification on how to determine the limits for integration.

Discussion Character

  • Homework-related
  • Conceptual clarification

Main Points Raised

  • One participant asks for guidance on how to evaluate the double integral and expresses confusion regarding the limits of integration.
  • Another participant suggests integrating with respect to y first, indicating a possible approach to the problem.
  • A participant clarifies that the limits 0 to 1 apply separately to both x and y, which is a point of confusion for some.
  • One participant attempts to articulate their understanding of the limits, stating that they need to find the upper limit for x and the lower limit for y, seeking confirmation on this interpretation.
  • Another participant reiterates that the notation used indicates that both x and y are bounded between 0 and 1, addressing the misunderstanding about the limits.
  • A later reply expresses gratitude for the clarification, indicating that the explanation helped resolve their confusion.

Areas of Agreement / Disagreement

Participants generally agree on the interpretation of the limits of integration, but there is some initial confusion regarding how to apply them in the context of the double integral.

Contextual Notes

Some participants express uncertainty about the specific roles of the limits in the integration process, and there is a lack of consensus on how to approach the evaluation of the integral itself.

hivesaeed4
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Evaluate ∫∫xexp(xy)dA,
and R (over which the integrand is to be integrated) is {(x,y)|0≤x,y≤1}.
Could someone explain how this is to be done.
 
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hi hivesaeed4! :wink:

dA = dxdy

try integrating wrt y first :smile:
 
My Bad. What I meant was what are the limits we should take for x and y. We are given one limit (either upper or lower limit) in each case. How do we find the second one for both x and y?
 
oh i see! :biggrin:

no, {(x,y)|0≤x,y≤1} is two limits …

the limits apply to both x and y (separately) :wink:
 
Look, let me tell you how I see the limits and correct me if I'm wrong.

The lower limit of x is 0. We have to find its upper limit.

The upper limit of y is 1. We have to find its lower limit.

The reason we have to find the upper limit of x and lower limit of y is that they are required for the integration.

Correct?

Also, please tell me how to find the upper limit of x and lower limit of y.
 
no, {(x,y)|0≤x,y≤1} is a shorthand way of saying {(x,y)|0≤x≤1} and {(x,y)|0≤y≤1} :wink:
 
Thanks tiny-tim. Thanks a lot. That question had me very confused.
 

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