How to explain the relationship: refractive index vs permitivity?

Click For Summary

Discussion Overview

The discussion revolves around the relationship between the refractive index and permittivity, specifically the equation n = √(ε*μ), where n is the refractive index, ε is the relative permittivity, and μ is the relative magnetic permittivity. The context includes inquiries about the derivation of this equation, with references to spectroscopy and the application of Maxwell's equations.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant seeks assistance in understanding the derivation of the equation relating refractive index to permittivity and magnetic permittivity.
  • Another participant suggests that Maxwell's equations are necessary for deriving the relationship.
  • There are comments about the appropriateness of the forum for this discussion, with suggestions to post in a different section.

Areas of Agreement / Disagreement

Participants generally agree that Maxwell's equations are relevant to the derivation, but the discussion does not reach a consensus on the specific steps or methods for obtaining the equation.

Contextual Notes

The discussion lacks detailed exploration of the mathematical steps involved in the derivation and does not clarify the assumptions or definitions related to permittivity and magnetic permittivity.

Yaohui
Messages
3
Reaction score
0
Any one can help deduct the process to obtain the following equation?
n= squart(ε*μ), n=refractive index, ε=relative permitivity, μ=relative magnetic permitivity.
I am reading a book relating to spectroscopy, and saw the above equation. I am really interested how the scientists got this equation. Thank you very much!
 
Physics news on Phys.org
You need to use Maxwell's equations.
 
  • Like
Likes   Reactions: vanhees71
...and post it in the classical-physics forum rather than in the textbook forum :-).
 
Dr_Nate said:
You need to use Maxwell's equations.
Thanks a lot!
 
vanhees71 said:
...and post it in the classical-physics forum rather than in the textbook forum :-).
Got it! Thank you!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 7 ·
Replies
7
Views
14K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
Replies
1
Views
2K