How to Express Function f in Terms of Complex Variable z?

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The discussion focuses on expressing the function f(x+iy) = (x-1-iy)/((x-1)^2+y^2) in terms of the complex variable z. Participants confirm that f satisfies the Cauchy-Riemann equations by separating it into real and imaginary components. To express f in terms of z, they suggest substituting x and y using z and its conjugate, leading to a simplified form. The numerator can be represented as z̅ - 1, while the denominator can be expressed using the relationship x^2 + y^2 = |z|^2. The conversation emphasizes mechanical steps and hints for a cleaner final expression.
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Let f(x+iy) = \frac{x-1-iy}{(x-1)^2+y^2}

first of all it asks me to show that f satisfies the Cauchy-Riemann equation which I am able to do by seperating into real and imaginary u + iv : u(x,y),v(x,y) and then partially differentiating wrt x and y and just show that \frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} , \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x} and then it asks to express f in terms of z i.e f(z) =...

I have no idea where to begin with this
 
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Hi SALAAH_BEDDIAF! :smile:
SALAAH_BEDDIAF said:
… express f in terms of z i.e f(z) =...

Well, the top is obviously ##\bar{z} - 1## …

what do you think the bottom might be? :wink:
 
write x and y in terms of z and its conjugate, then simplify

$$x=\frac{z+\bar{z}}{2}\\y=\frac{z-\bar{z}}{2 \imath}$$
 
To start, you definitely want to express it in terms of z and \bar z.

You can use lurflurf's hint and do it mechanically.

If you want something slightly cleaner...
- Use tiny-tim's hint for the numerator.
- Expand the denominator, and use x^2+y^2 = |z|^2 (Pythagoras), which can itself be expressed cleanly as z\bar z.
- On what's left (cleaner than before), use lurflurf's hint.
 
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