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How to find acceleration from distance and time?

  1. Apr 16, 2015 #1
    1. The problem statement, all variables and given/known data
    The problem is asking to find acceleration from distance and time measurements. It is also asking to find acceleration from newtons second law

    This was a linear air track lab if you're wondering.

    Whats given:
    Distance = 81 cm
    Total mass moved = 200g
    Weight Force = 1.471N (150g)
    Time = 0.003 secs (This might be wrong, but forget it. I just want to know how to calculate acceleration)

    2. Relevant equations
    S=ut+0.5*a*t^2

    Where
    S = distance
    u= Initial velocity
    a= accleration
    t=time

    3. The attempt at a solution
    So,

    0.81m = (0)(0.003)+(0.5)(0.003)^2(a)
    0.81m=4.5x10^-6a
    a= 1.8x10^-7 m/s^2

    I am using the formulas from this website
    http://www.mathalino.com/reviewer/engineering-mechanics/motion-particle
     
  2. jcsd
  3. Apr 16, 2015 #2
    Here is my second attempt

    where v = final velocity

    v+u=2s/t
    v=2s-u/t
    v=2(0.81)-0/0.003
    v=540 m/s^2

    v-u/t
    540-0/0.003

    a= 18,000 m/s^2
     
  4. Apr 16, 2015 #3

    haruspex

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    You seem to be having some trouble with the arithmetic.
    All was fine until the last step. try that again.
    You mean m/s.
    You mean (540-0)/0.003.
    Again, you made an arithmetic mistake at the last step.
     
  5. Apr 16, 2015 #4
    Yea thanks I got 180,000 m/s on both

    On the first one 0.81/4.5x10^-6
    =180,000 m/s

    second one

    540-0/0.003
    =180,000 m/s

    So the steps I did are correct?
     
  6. Apr 16, 2015 #5

    haruspex

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    Yes.
     
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