How to find angle after applying Pythagorean Theorem?

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Homework Help Overview

The discussion revolves around a problem involving the application of the Pythagorean theorem in a three-dimensional context to find an angle related to an object's position in space. The original poster describes an object located 4 km above, 1.4 km to the north, and 2 km to the west, seeking guidance on how to determine the angle to this object.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to visualize the problem through drawing and marking angles. There is mention of needing to identify which angle is of interest, as well as the implications of working in three dimensions, which requires understanding multiple angles.

Discussion Status

Some participants have offered guidance on visualizing the problem and identifying the relevant angles, while others have raised questions about the completeness of the information provided and the need for clarity on the specific angle being sought. The conversation reflects a mix of interpretations and approaches to the problem.

Contextual Notes

There is uncertainty regarding the initial setup of the problem, particularly in how to accurately draw the scenario and the assumptions about angles in three-dimensional space. The original poster expresses confusion about the measurements and their relationship to the axes.

LeighV
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Hello, so I have a question that states (these aren't the actual measurements but they are around about the same, I can't remember the exact numbers so I made these up, this way I could apply the same to the actual numbers) an object being 4km above me, 1.4km to the north of me, and 2km to the west of another person. (I know the coordinates north, west, etc. are correct, just made a guess on the numbers) I have to find the angle to the object.

So i began for the xyz to begin applying the Pythagorean theorem, so
√4^2 + 1.4^2 + 2^2
16 + 1.96 + 4
4.69

But I am not sure where to go from here. I am guessing it would be either cos or sin I use?

Thank you for the guidance!
 
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Draw a picture and mark your angle then it should be obvious which trig function to use.

Since you know all three sides, you get to choose your favorite one.
 
Since you apparently are dealing with a 3-D problem, you'll need more than one angle to determine the location of this point. After all, in 3-D, you need 3 pieces of information to determine a specific location.
 
The thing is I don't even know where to begin with drawing it out...I did attempt to but it never seemed to measure out correctly. @SteamKing it is a really confusing problem because that is the only information they give me, unless I count the north or west measurement as being a 90 degree angle against the axis?
 
LeighV said:
Hello, so I have a question that states (these aren't the actual measurements but they are around about the same, I can't remember the exact numbers so I made these up, this way I could apply the same to the actual numbers) an object being 4km above me, 1.4km to the north of me, and 2km to the west of another person. (I know the coordinates north, west, etc. are correct, just made a guess on the numbers) I have to find the angle to the object.
It's a good question, but before you can answer it you must identify the angle you are interested in. You want the angle between that vector you described and what? Perhaps between that vector and another vector? Or between that vector and the x-y plane?

If the latter, then you are looking for the angle between the vector and its "shadow" on the x-y plane.

This article will get you started. Run through it quickly first, then back up and read more thoroughly. http://www.intmath.com/vectors/7-vectors-in-3d-space.php#anglebetweenvectors
 

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