How to find derivative of tanh^-1(x)

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SUMMARY

The derivative of tanh-1(sinh(2x)) is calculated using the Chain Rule. The correct formula is given by the expression: d/dx(tanh-1(sinh(2x))) = (1 / (1 - sinh2(2x))) * (2cosh(2x)). This involves differentiating the outer function tanh-1(x) and the inner function sinh(2x) simultaneously. The final result simplifies to (2cosh(2x)) / (1 - sinh2(2x)).

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how do I find the derivative of tanh^-1(sinh(2x))

do I just find derivative of tanh^-1(x) this then substitute sinh(2x) into x??
 
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sozener1 said:
how do I find the derivative of tanh^-1(sinh(2x))

do I just find derivative of tanh^-1(x) this then substitute sinh(2x) into x??

Yes, but since the Chain Rule applies here, you must not forget the inner derivative.

It is also possible that this can be rewritten and simplified, but I'm too tired to figure this out now...
 
Chain Rule, Chain Rule, Chain Rule!
\frac{d}{dx} (\tanh^{-1} \sinh 2x) = \frac{d}{dx} (\tanh^{-1} \sinh 2x) \cdot \frac{d}{dx} \sinh 2x = \frac{1}{1 - \sinh^2 2x} \cdot 2\cosh2x
Thus,
\frac{d}{dx} (\tanh^{-1} \sinh 2x) = \frac{2 \cosh 2x}{1 - \sinh^2 2x}
 

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