How to find equilibrium temperature of a system

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Homework Help Overview

The problem involves a gas in an insulated box divided by a partition, where two portions of gas at different temperatures are allowed to reach thermal equilibrium. The inquiry includes determining the equilibrium temperature under various conditions and exploring the implications of adding a small amount of milk to hot tea.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the concept of energy conservation in an isolated system and how thermal energy redistributes. There is consideration of how temperature relates to thermal energy, with some questioning the initial assumption that equilibrium temperature could simply be the sum of the two initial temperatures.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about temperature and energy. Some guidance has been offered regarding the relationship between thermal energy and temperature, though no consensus has been reached on the specific approach to finding the equilibrium temperature.

Contextual Notes

There are constraints regarding the lack of specific heat or mass information in the problem statement, which participants are acknowledging as they explore potential solutions.

hunterstein
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Homework Statement



A gas is in an insulated box, which is divided into two portions by an insulated partition. There are n1 moles of the gas at temperature T1 in volume V1, and likewise n2 moles of the (same) gas at temperature T2 in volume V2. The partition is composed of two layers; one layer is insulating (e.g. mashed newspaper) and the other layer is not (e.g., metal). The insulating layer is gently removed, but the non-insulating partition remains. The system is allowed to come to equilibrium.

a) What is the equilibrium temperature of the system?
b) If n1 = n2 what is the equilibrium temperature?
c) Use your result to find the equilibrium temperature for the situation when a small amount of milk is added to very hot tea. More precisely, let = n1/n2 and let δ = T1/T2 and assume that 1 and δ 1. Then expand the expression for the equilibrium temperature to first order in and to first order in δ. You can do this by first expanding in one parameter, then the other.

Can someone help me out with this? Please do not feed me the answer, I need to learn and understand this subject
 
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Think about it in terms of energy. The system has a certain amount of energy in the form of thermal/kinetic energy. Since it is isolated from the environment the total thermal energy will not change, just redistribute. Does that help?
 
LunaFly said:
Think about it in terms of energy. The system has a certain amount of energy in the form of thermal/kinetic energy. Since it is isolated from the environment the total thermal energy will not change, just redistribute. Does that help?

I was thinking like that, and the first thing that popped into my head is that the equilibrium Temperature would be T1 + T2, but that can't be right
 
hunterstein said:
I was thinking like that, and the first thing that popped into my head is that the equilibrium Temperature would be T1 + T2, but that can't be right
That's not quite right. The temperature of the system isn't a constant. The thermal energy is what's constant. How does the temperature relate to thermal energy? (there is an equation...)
 
LunaFly said:
That's not quite right. The temperature of the system isn't a constant. The thermal energy is what's constant. How does the temperature relate to thermal energy? (there is an equation...)

E= c * m * deltaT? I was thinking that had something to do with it, but specific heat or mass isn't mentioned at all.
 
hunterstein said:
E= c * m * deltaT? I was thinking that had something to do with it, but specific heat or mass isn't mentioned at all.
Just think of one of the gas volumes to start with. If a quantity of heat ##\Delta Q## escapes, what remains constant? What is the resulting temperature? If you need to invent an unknown for specific heat, do so. Maybe it will cancel later on.
 

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