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Pressure/Temperature mechanical equilibrium

  1. Feb 7, 2015 #1


    1. The problem statement, all variables and given/known data


    Three thermally insulated containers of equal volume are connected together by thin tubes of negligible volume so that gas can flow from one container to the next when a valve between them is open. Initially, the pressure and temperature in each container is at the same value Po and To, respectively.

    The valves between the vessels are opened, and thermal insulation is removed from two of the vessels. Then two vessels are surrounded by heat reservoirs so that their temperatures are maintained at 2To and 2.3To while the third remains at To. What is the final pressure of the system when mechanical equilibrium is reached?

    2. Relevant equations

    P0/T0 = P1/T1 = P2/T2 .....


    3. The attempt at a solution

    Very stuck. Sorry for bad english

    This problem was labeled in my text as a quick easy review, however I cannot seem to make any progress as to solve it. The answer given is 1.55Po.

    My initial attempt was to work with PV=nRT, and try to relate the individual "new" pressures to their old pressures, then proceed to sum them up.

    Meaning, I was told they each originally had P0/T0 , so for vessel one, I set this equal to
    P1/2T0 . I did this for the remaining cases and solved the new pressures in terms of Po, however I soon got stuck and it didn't lead me anywhere.
     
  2. jcsd
  3. Feb 7, 2015 #2

    haruspex

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    You're overlooking that gas flows from one to another, so n doesn't stay constant for each.
    But n for the whole system is constant. Assign separate variables for the final molecular quantities in the three containers.
     
  4. Feb 7, 2015 #3
    If I understand correctly, I need to also examine the change in n.

    P0/(T0n0) =P1/(2T0nf1) =P2/(2.3T0nf2) =P3/(T0nf3)

    Is this the necessary relationship? If so, I suppose I raise another question, is the sum of the individual pressures equal to the total pressure of the system once mechanical equilibrium is achieved?

    I apologize for the many questions, I am trying to understand some of this material before the topics are introduced.
     
  5. Feb 7, 2015 #4

    haruspex

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    Yes.
    These pressures don't add together, they're not partial pressures of a gas mixture. What will happen if the pressures are different? Is that equlibrium?
     
  6. Feb 7, 2015 #5
    If V is the volume of each tank, what is the number of moles in each of the tanks to start with?

    What is the total number of moles in the tanks to start with?

    If P is the pressure in the three tanks in the final equilibrium state, what is the number of moles in each of the tanks at the end (in terms of P)?

    What do the final number of in the three tanks have to add up to?

    Chet
     
  7. Feb 7, 2015 #6
    Each tank starts with n0, therefore, the total is 3n0. Also since the pressure in one tank is P0, this must also mean the pressure of the system (all tanks) is P0 ; I should be able to say the same for the temperature.

    So, before anything happens, I have P0/(3n0T0) , assuming n0 represents the number of moles in each tank. Is what I have stated true?

    If so, the other side of the expression will be straight forward for me.
     
  8. Feb 7, 2015 #7
    No. Not even close. The number of moles of gas initially in each tank is, using your notation, ##n_0=\frac{P_0V}{RT_0}##. The total number of moles in the 3 tanks is
    $$3n_0=3\frac{P_0V}{RT_0}$$

    Chet
     
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