# How to find initial velocity with height, distance and angle

## Homework Statement

We need to fin the initial velocity of a water fountain. The data I have collected is:
Height (bottom to apex)= 0.042 m
Distance (from spout to end on the stream)= 0.112 m
Time (it takes to travel)= .25 seconds
Angle the water shoots from= 50 degrees

Here is more if it helps.
Vertical
- D= .042 m
- T= .25 s
- Vfinal= 0 m/s
- a= 9.8 m/s2
- angle= 50 degrees
Horizontal
- D= .112 m
- T= .25 s
- angle= 50 degrees

## Homework Equations

V= d/t, This can be used to find the horizontal component ( in the x direction) because Vxcomponent= average velocity.
Vycomponent= vertical initial velocity
vf= vi + at
d=Vi *t +1/2at2
a= acceleration t= time d=distance ( only used with Vertical data)

## The Attempt at a Solution

I know that I must find the x and y component vectors but I do not know what equation to use. I tried this four different ways and got four different answers and I'm just really frustrated. I was told to use the vf= vi + at equation for the vertical component and the v=d/t for the horizontal, and they said something about half time, I dont know.

haruspex