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## Homework Statement

We need to fin the initial velocity of a water fountain. The data I have collected is:

Height (bottom to apex)= 0.042 m

Distance (from spout to end on the stream)= 0.112 m

Time (it takes to travel)= .25 seconds

Angle the water shoots from= 50 degrees

Here is more if it helps.

__Vertical__

- D= .042 m

- T= .25 s

- Vfinal= 0 m/s

- a= 9.8 m/s

^{2}

- angle= 50 degrees

__Horizontal__

- D= .112 m

- T= .25 s

- angle= 50 degrees

## Homework Equations

V= d/t, This can be used to find the horizontal component ( in the x direction) because Vxcomponent= average velocity.

Vycomponent= vertical initial velocity

v

_{f}= v

_{i}+ at

d=V

_{i}*t +1/2at

^{2}

a= acceleration t= time d=distance ( only used with Vertical data)

V

_{f}

^{2}= v

_{i}

^{2}+ 2ad

## The Attempt at a Solution

I know that I must find the x and y component vectors but I do not know what equation to use. I tried this four different ways and got four different answers and I'm just really frustrated. I was told to use the v

_{f}= v

_{i}+ at equation for the vertical component and the v=d/t for the horizontal, and they said something about half time, I dont know.